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(nT / pv)1 = (nT / pv)2

(n x 250) / (101 x 1L) = (1mole x 273)/(101.325 x 22.4L)

n = 0.0486 mol

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Q: How many moles of air are in a 1.00 L at -23oC and 101 kPa?
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