The balanced chemical equation for the formation of water from ammonia is: 2 NH₃ + 3 O₂ → 2 H₂O + N₂. According to the equation, 2 moles of ammonia produce 2 moles of water. Therefore, to produce 13.8 moles of water, you would require 13.8 moles of ammonia, since the ratio is 1:1.
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------
To produce water (H₂O), the balanced chemical equation is 2 H₂ + O₂ → 2 H₂O. From this equation, we see that 1 mole of O₂ produces 2 moles of H₂O. Therefore, to produce 1.60 moles of water, you would need 0.80 moles of O₂ (1.60 mol H₂O × 1 mol O₂ / 2 mol H₂O = 0.80 mol O₂).
2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water
To form water (H₂O), the balanced chemical reaction is 2 H₂ + O₂ → 2 H₂O. This indicates that 2 moles of hydrogen gas (H₂) are required to produce 2 moles of water (H₂O). Therefore, for 8.12 moles of H₂O, you would need 8.12 moles of H₂, as the ratio of H₂ to H₂O is 1:1.
H2O (water) and NH3 (ammonia) can mix and form a homogeneous solution in certain circumstances, such as when diluting ammonia in water or using them as solvents. However, ammonia is a weak base and can react with water to produce ammonium and hydroxide ions.
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
To produce 1 mole of water, you need 2 moles of hydrogen. Therefore, to produce 7.4 moles of water, you would need 2 * 7.4 = 14.8 moles of hydrogen.
3.2 moles of water (H2O)
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------
To produce 1 mol of water, 2 mol of hydrogen is needed. Therefore, to produce 7.5 mol of water, you would need 15 mol of hydrogen.
To determine the grams of hydrazine (N2H4) needed to produce 96.0 grams of water (H2O), we start with the balanced chemical equation for the reaction: 2 N2H4 + 2 O2 → 4 H2O + N2. From this equation, we see that 2 moles of hydrazine produce 4 moles of water. The molar mass of water is approximately 18 g/mol, so 96.0 g of water corresponds to 5.33 moles of water. This means 2.67 moles of hydrazine are required, which equals about 66.3 grams of hydrazine (with a molar mass of 32.05 g/mol).
Ammonia gas dissolves in water to produce a solution with a pH of 11. This is because ammonia reacts with water to form ammonium hydroxide, which is a weak base, causing the solution to be basic.
2H2 + O2 ---> 2H2O 3.5 mole of hydrogen will produce 3.5 mole of water.
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
You need to write a balanced reaction and then use stoichiometry to solve this problem.First write a balanced reaction. The reactants are O2 and NH3 and the products are HNO3 and H2O. For step-by-step instructions on how to balance a reaction, see the Related Questions link to the left.Then use stoichiometry to solve the problem. See the Related Questions to the left for step by step instructions on how to do that! And don't forget to convert the 402 kg of water into moles!
1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. Therefore, 10.0 moles of water will produce (10/6)*4 moles of H3PO4. To convert moles to grams, multiply the number of moles by the molar mass of H3PO4.
Ammonia water is a base chemically, if it reacts with an acidic substance it will produce a salt that is dissolved in the water..