We calculate the numerator of the desired probability:
There are 6 ways any number can show up on the first die
AND
There is only 1 way that same number can show up on the second die
So since "AND" means "MULTIPLY", there are 6x1 or 6 ways
that both dice can come up the same. So the numerator of
the probability is 6.
We calculate the denominator of the desired probability:
There are 6 ways any number can show up on the first die
AND
There are 6 ways any number can show up on the second die
So since "AND" means "MULTIPLY", there are 6x6 or 36 ways
the two dice can all come up any number. So the denominator
of the probability is 36.
11 outcomes if the dice are indistinguishable, 36 otherwise.
The sample space for 1 roll is of size 6.
There are 36 possible outcomes of rolling two dice.
a lot
There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.
11 outcomes if the dice are indistinguishable, 36 otherwise.
There are 36.
There are 64 = 1296 of them.
Assuming traditional cubic dice, the sample space consists of 216 points.
Not sure about the relevance of sizzle! The size of the sample space is 46656.
The sample space for 1 roll is of size 6.
impossible or 1/6 * * * * * No! The sample space refers to the set of possible outcomes, not the probability of any one outcome.
1, 2, 3, 4, 5, 6
5 and 1.
The set of all possible outcomes of a random experiment is nothing but sample space usually denoted by S. we can also call it as event. For example our experiment is rolling a dice, then our sample space is S= {1,2,3,4,5,6}
There is 6 possible outcomes per roll of a die. So, there are 6*6*6*6 outcomes or 64 or 1296 possible outcomes.
If we roll 2 dice simultanosly the sample space consists of 6 rows and 6 col so the answer is 6*6 i.e 36 elements.If we roll 6 dice simultanosly the sample space consists of 36 rows and 36 col so the answer is 36*36 i.e 1296 elements.