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λ - wavelength (NM) c - speed of light (3x108 m/s)= 162 000 nm

f - Frequency (Hz)

λ = c \ f

600=162 000 nm\ f f=270 Hz

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14y ago
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10y ago

There can be as little as one if it has the right energy for that wavelength, number of photons has nothing to do with wavelength. The number of photons only determines the intensity/brightness.

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15y ago

You don't, as the wavelength is totally independent of the number of photons. You could have one or a trillion different photons, each of 600nm.

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13y ago

So I'm guessing that you go to Georgia Southern?

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10y ago

i got 3.3*10^-19... im not positive. so if you need anthing to check your work on... that is my solution

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12y ago

Energy = hf=hc/r = 1.25uevm/.589um=2.12 electron volts.

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Q: How do you calculate the number of photons that corresponds to 600 nm of light?
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