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Answered 2013-01-20 06:05:15

Two possible outcomes for each flip.

2,048 possible histories of 11 flips.

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There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)


Heads - ½ Tails - ½ There are two reasonable outcomes of flipping a coin. You could get heads or tails. Some might argue that the third outcome is that the coin will land on the edge.


If a coin is tossed 15 times there are 215 or 32768 possible outcomes.


There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.


There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.


There are 26 = 64 possible outcomes.



Flipping a coin: two possible outcomes, H or T. Rolling a die: six possible outcomes, 1, 2, 3, 4, 5, or 6. Flipping a coin and rolling a die: 12 possible outcomes. So the sample space has 12 outcomes such as, {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6 }


If you flip a coin 2 times, there are 4 possible outcomes; HH, HT, TH, TT.


There are 2 * 6 or 12 outcomes for flipping a coin and spinning a spinner that has 6 different colored sections.


There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.


In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.


2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.


The possible outcomes of a coin that is flipped are heads or tails.


The probability of throwing exactly 2 heads in three flips of a coin is 3 in 8, or 0.375. There are 8 outcomes of flipping a coin 3 times, HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT. Of those outcomes, 3 contain two heads, so the answer is 3 in 8.



The sample space for this situation is all the possible outcomes that could be achieved. Like H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, and T6 are the outcomes for flipping a Coin and rolling a number cube.


when you toss a coin three times, the total number of possible outcomes is



When flipping a coin, there are 2 possible outcomes. When flipping 3 coins there are 8 possible outcomes (2^3=8). As for the situation described, there is only one way for it to not be true, if all the coins land on the same side. So either all heads or all tails. This leaves 8-2=6 possible outcomes resulting in the above situation. Therefore the probability of the given situation is 6/8 or 3/4=75%


The cube has 6 possible outcomes.The coin has 2 possible outcomes.There are 6 x 2 = 12 possible outcomes for a trialthat involves both the cube and the coin.


Two times the number of outcomes of the spin - which is not specified in the question.


The coin can result in one of two possibilities. For each of those . . .The cube has 6 possibilities.Total possibilities for the coin and the cube = 2 x 6 = 12 .




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