Math and Arithmetic
Statistics
Probability

# How many possible outcomes of tossing a coin 6 times?

123

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There are 26 = 64 possible outcomes.

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## Related Questions

There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)

The cube has 6 possible outcomes.The coin has 2 possible outcomes.There are 6 x 2 = 12 possible outcomes for a trialthat involves both the cube and the coin.

Heads or tails; each have a probability of 0.5 (assuming a fair coin).

Do you mean what are all the possible outcomes? Or what is the probability of a certain outcome? Need a little more information.

The outcomes are: heads, tails, tails or tails, heads, tails or tails, tails, heads. You can see that there are 3 possible outcomes with exactly 1 head.

A system with two possible outcomes with equal probabilities.

It is used to represent one of the two possible outcomes of tossing a coin.

If a coin is tossed 15 times there are 215 or 32768 possible outcomes.

There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.

There are 2^5 (2*2*2*2*2), or 32, possible outcomes of tossing a coin 5 times. Only one of those outcomes does not contain any tails. This leaves us with 31/32, or 97% chance of at least one toss coming up tails.

If you flip a coin 2 times, there are 4 possible outcomes; HH, HT, TH, TT.

2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.

The possible outcomes of a coin that is flipped are heads or tails.

Two possible outcomes for each flip. 2,048 possible histories of 11 flips.

Each coin can come out either heads (H) or tales (T). Since you're tossing four coins at once, I'm assuming there is no sense of order to be accounted for. In that case, the possible outcomes are the following: HHHH HHHT HHTT HTTT TTTT

when you toss a coin three times, the total number of possible outcomes is

There are sixteen different outcomes. To figure this you multiply the number of possible outcomes for each coin, which is 2 for all of them. So you take 2^4 which comes out to 16.

That's the same as the highest binary number you can write with 30 bits.It's 230 = 1,073,741,824 .Get started.

The sample space for rolling a die is [1, 2, 3, 4, 5, 6] and the sample space for tossing a coin is [heads, tails].

Two times the number of outcomes of the spin - which is not specified in the question.

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