The possible number of remainders is always one less than the divisor.
There are 28 remainders, including zero.
For numbers 0-23 , the remainder will range from 23-0 . After 23 , the same range of remainders will repeat. Hence , when 23 is the divisor , there are 24 possible remainders , 0-23.
The possible number of remainders is always one less than the divisor.
Only 3 non-zero remainders.1, 2, and 3 are the only possible non-zero remainders since any number greater than or equal to the divisor could also be divided, to result in a new quotient. A remainder of zero, means that the dividend is divisible by the divisor (the divisor is a factor of the number)
There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.
There are 10 possible divisors, the numbers 0 to 9.
The remainder can be anything from zero to 20 ... 21 possibilities.
For numbers 0-23 , the remainder will range from 23-0 . After 23 , the same range of remainders will repeat. Hence , when 23 is the divisor , there are 24 possible remainders , 0-23.
To determine the remainder when dividing 63 by a divisor, you need to perform the division and look at the remainder. For example, if you divide 63 by 5, the remainder is 3. However, if you divide it by 7, the remainder is 0.
Walang remainder
The possible number of remainders is always one less than the divisor.
Only 3 non-zero remainders.1, 2, and 3 are the only possible non-zero remainders since any number greater than or equal to the divisor could also be divided, to result in a new quotient. A remainder of zero, means that the dividend is divisible by the divisor (the divisor is a factor of the number)
There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.
There are 10 possible divisors, the numbers 0 to 9.
With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.
The divisor is missing. Please edit the question to include the relevant information.
If the dividend is a multiple of 8 then there will be no remainders in the quotient otherwise the possible remainders are limitless
8 integer remainders. From 0 to 7 (inclusive).