1 1 .There are 6 rules for Significant figures.(SF). Non zero digits count as sf. Ex 34.5=3 Sf and 4367=4 Sf. 2. Leading zeros never count Ex 0.34= 2 Sf and 0.00399 = 3 sf 3. Zeros between sf count ex 405=3sf and .0402=3 sf and 20000.1=6 sf 4.IF a number shows a decimal point ending zeros count. Ex 25.0=3 sf and 10.0= 3 sf and 0.004500=4 sf 5. If a number does not show a decimal point, ending zeros dont count. Ex 500=1 sf and 25000 = 2 sf and 10= 1 sf 6. If a number is written is correct scientific notation, then all digits in fornt of (x10) count. Ex 2.4x10^5 = 2 sf and 3.00x10^8 = 3sf
Four
There are 4 significant digits. If zeros are specified at the end to the right of the decimal point, then they are significant. If the number was 5.000 x 101, then it would be 4 as well. If it were just 50, then there would be 1 significant digit.
However, if the zeros to the right are there for conventional reasons (for example to denote 50 units of currency), then it could be 2 or even 1 sig digits.
Three. All non-zero numbers are significant.
There are 2 * * * * * Unless the trailing 0s are simply place holders, the correct answer is 4. If they ARE place holders, the correct answer is 1.
There are 3 significant figures in 56.0. Have fun with the rest of your Chemistry homework!
Three- 5,6,0
* * * * *
No.
The 0 is NOT a significant digit, it is merely a place holder. There are only 2 significant digits.
Four. All nonzero digits are significant and zeros in between significant digits are always significant.
4 significant figures and.
3 significant figures.
3
1,071 has four significant digits.
You have to round to two significant digits because 5.5 only has two. So, 5.5 × 2.141 = 12
There are four significant digits in 11.00.
Five - all nonzero digits are significant.
Three - all nonzero digits are significant.
Three significant digits.
This number has seven significant digits.
All four of the digits given are significant digits.
There are two significant digits in the number 83.
1,071 has four significant digits.
All numbers which are not "zero" are classed as significant digits. Therefore in the number 129 there will be three digits which are classed as significant.
Two. All nonzero digits are significant.
There are 2 significant digits: 5 and 4
All the digits are significant, so there are 5 significant digits.
There are 5 significant digits in number 14500. To count for a given number as to how many significant digits does it have, look for the first zero form left and decimal point. For ex sample 0045 has 2 significant digits 0.0045 has 2 significant digits 0.4500 has 4 significant digits.
0.00909 has three significant digits.
Three: The first two zeros are not significant digits.