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For this area you will need 2.4 cubic yards.
Area=64ft. Times 4in or .3ft deep.. 64ft x 0.3ft x5= 96ft3.
About 115-120 pounds!
90.25 in a fraction = 361/4 90.25 * 100/100 = 9025/100 or 361/4in fraction in lowest term
Well im not sure but i know a way you can find out. You take the height of when you were 2 years old in centimetres and then multiply it by 2 and then put it into feet. I am 12 years old and 5.4 and my answer was 5.9.
You will need 3.7 cubic yards of cement.
For this area you will need 2.4 cubic yards.
about 25 yds
4ft 4in (132cm)
If you mean 12 feet long by 8 inches wide by 4 inches deep, you will need at least 0.1 cubic yards
There are 100 inches in 8ft 4in
4in is less than 1 ft so 4in is a fraction of a foot 4/12 = 1/3 4in = 1/3ft = .33 ft
4in
Yes. I would use a peagravel mixture with fibermesh additive. Pressure wash the area first if possible.
that is 333 cubic feet,or 12.3 cubic yards At 100 pounds per cubic foot,that is over 33,000 pounds of gravel
Area=64ft. Times 4in or .3ft deep.. 64ft x 0.3ft x5= 96ft3.
How many triangles exist with the given side lengths 3in, 4in, 2in