Math and Arithmetic

Statistics

Probability

Top Answer

Roughly half of the time, so about 350 times.

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0A fair coin would be expected to land on heads 75 times.

They are HHT HTH and THH

A fair coin would be expected to land on heads 10 times on average.

The correct answer is 1/2. The first two flips do not affect the likelihood that the third flip will be heads (that is, the coin has no "memory" of the previous flips). If you flipped it 100 times and it came up heads each time, the probability of heads on the 101st try would still be 1/2. (Although, if you flipped it 100 times and it came up heads all 100 times - the odds of which are 2^100, or roughly 1 in 1,267,650,000,000,000,000,000,000,000,000 - you should begin to wonder about whether it's a fair coin!). If you were instead asking "What is the probability of flipping a coin three times and having it land on "heads" all three times, then the answer is 1/8.

It is neither. If you repeated sets of 8 tosses and compared the number of times you got 6 heads as opposed to other outcomes, it would comprise proper experimental probability.

The probability of flipping a coin 24 times and getting all heads is less than 1 in 16 million. (.524) It would seem that no one has ever done that.

The probability of a heads is 1/2. The expected value of independent events is the number of runs times the probability of the desired result. So: 100*(1/2) = 50 heads

The expected number is 3750.

There is a fifty percent chance of the coin landing on "heads" each time it is flipped.However, flipping a coin 20 times virtually guarantees that it will land on "heads" at least once in that twenty times. (99.9999046325684 percent chance)You can see this by considering two coin flips. Here are the possibilities:Heads, heads.Heads, tails.Tails, tails.Tails, heads.You will note in the tossing of the coin twice that while each flip is fifty/fifty, that for the two flip series, there are three ways that it has heads come up at least once, and only one way in which heads does not come up.In other words, while it is a fifty percent chance for heads each time, it is a seventy five percent chance of seeing it be heads once if you are flipping twice.If you wish to know the odds of it not being heads in a twenty time flip, you would multiply .5 times .5 times .5...twenty times total. Or .5 to the twentieth power.That works out to a 99.9999046325684 percent chance of it coming up heads at least once in the twenty times of it being flipped.

This is a binomial probability distribution The probability of exactly 2 heads in 50 coin tosses of a fair coin is 1.08801856E-12. If you want to solve this for how many times 50 coin tosses it would take to equal 1 time for it to occur, take the reciprocal, which yields you would have to make 9.191019648E11 tosses of 50 times to get exactly 2 heads (this number is 919,101,964,800 or 919 billion times). If you assume 5 min for 50 tosses and 24 hr/day tossing the coin, it would take 8,743,360 years. That is the statistical analysis. As an engineer, looking at the above analysis, I would say it is almost impossible flipping the coin 50 times to get exactly 2 heads or I would not expect 2 heads on 50 coin tosses. So, to answer your question specifically, I would say none.

This is a binomial probability distribution The probability of exactly 2 heads in 50 coin tosses of a fair coin is 1.08801856E-12. If you want to solve this for how many times 50 coin tosses it would take to equal 1 time for it to occur, take the reciprocal, which yields you would have to make 9.191019648E11 tosses of 50 times to get exactly 2 heads (this number is 919,101,964,800 or 919 billion times). If you assume 5 min for 50 tosses and 24 hr/day tossing the coin, it would take 8,743,360 years. That is the statistical analysis. As an engineer, looking at the above analysis, I would say it is almost impossible flipping the coin 50 times to get exactly 2 heads or I would not expect 2 heads on 50 coin tosses. So, to answer your question specifically, I would say none.

25. In one throw the odds are 2/8. That is, th ere are 8 possible outcomes, two of which are considered "winning" combinations (HHH and TTT). In 100 throws, you would expect each of the 8 outcomes to occur 12 or 13 times (the average of the number of times each of the 8 outcomes occurs will always be exactly 12.5, whether the distribution is even or whether you got all heads all 100 throws and all the other combinations were zero). You would expect the number of times you get all heads or all tails - two of those combinations - to be 25.

Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.

You can expect to get a 5 about 15 times out of 90.

Less. The more times the coin is tossed, the more likely it will reflect the actual odds of .5 heads and .5 tails.

A fair coin means that the probability of a head = probability of a tail = 1/2 So you would expect half the tosses to be heads, ie 1/2 x 75 = 371/2 heads. ...oooOOOooo... Having 1/2 a head doesn't seem possible, but when the question asks about expectation, it is saying: if you repeated the experiment lots of times, how often, on average, would the required result appear. So the expectation of heads when a fair coin is tossed 75 times is asking: if a fair coin was repeatedly tossed 75 times, what would be the (mean) average number of heads achieved? As more and more trials are done and the (mean) average of the number of heads got is taken, it will get closer and closer to 371/2 37 or 38 times. (Obviously, you can't have half of a time.) You will either get one or the other, and a fair coin means that either is just as likely. So, it should split evenly down the middle.

With a fair die, you would expect it 60*(1/6) = 10 times.

Testing large groups rules out statistical anomalies. For example, one could flip a coin and have it be heads twice in a row. From this example, it might be deduced that the coin only lands on heads. If one flips the coin several thousand times, they would likely see a relatively close amount of heads and tails being flipped.

He should expect it 100 times.

You would expect it 0.3 of the times.

You can expect the spinner to land an odd number 25 times out of 50.

Every time you flip a coin it has a 50% probability that it will land on either heads or tails. You would expect to get heads about half the time and tails about half the time. What actually happens could be different from what is expected. You could get heads every time, or tails every time. Or you could get tails 75% of the time and heads 25% of the time. however, your results appear to be what you would expect, approximately 50% heads and 50% tails. You got 16 heads and 14 tails. Your percentage of heads is 16/30 x 100= 53.33... %. Your percentage of tails is 14/30 x 100 = 46.66... %.

the directions, like on a compass, would be flipped as well as the magnetic fields. North would be the current south, and south would be the current north.

the probability is actually not quite even. It would actually land heads 495 out of 1000 times because the heads side is slightly heavier

1/6 of 300 = 50 times.

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