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In order to be divisible by both 2 and 3, a number must be divisible by 6.

The largest multiple of 6 less than 100 is 96 ... the 16th multiple of 6.

So there are 16 of them.

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0There are 75 whole numbers from 100 to 999 that are divisible by both three and four.

between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.

Numbers are divisible by their factors. Multiples are divisible by their numbers.

The lists of numbers divisible by and not divisible by 600 are both infinite.

0,12,24,36,48,60,72,84, and 96 are the numbers between 0 and 100 that are divisible by both 3 and 4.

The numbers divisible by both 3 and 4 are multiples of 12, thus between 10 and 99: 12, 24, 36, 48, 60, 72, 84, 96 are the numbers divisible by both 3 and 4.

numbers between 10 and 20 is divisible by both 4 and 6 = 12 & 18

33 divisible by 3. 14 divisible by 7. 4 divisible by both. Total: 43

If you mean how many can be divided by both 2 and 3, then it would be the multiples of 6 between 1 and 100: This would be numbers of the form 6k, where k is a whole number. There are 16 values of k for which 1<=6k<=100 [I don't think I can make a proper less than or equal sign on here, so I am using "<="]. k=1,2,3,4,...,16, with 6k=6,12,18,...96 If you mean how many are divisible by either 2 or 3 (or both), this would be the number of whole numbers divisible by 2+the number of whole numbers divisible by 2-the number of whole numbers divisible by 6 [to eliminate double counting]. By the same rationale applied above for 6, there are 50 numbers between 1 and 100 inclusive that can be divided by 2, and 33 numbers that can be divided by 3. So there are are 50+33-15=73 that can be divided by either 2 or 3 (or both).

Two numbers: 126 and 147

Four. 24 and its multiples.

The are six such numbers: 18,36,54,72, 90 and 108 .

Prime numbers (except for 5) can't be divisible by 5.

972 is one of the numbers that is divisible by both.

both are multiples of 4, 2, and 8 because they're divisible by 2, they're even numbers Both are positive integers (whole numbers greater than 0)

It doesn't have a numerical answer. If both numbers are even, one will be divisible by the other.

193 of them are divisible by one (or more) of the given numbers.

No, they are both even and odd. The numbers 18 and 36 are examples of even numbers divisible by nine.

How many numbers less than 700 are divisible by both 15 and 21?

Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.

They are both divisible by two.

Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33

The smallest whole number divisible by both 8 and 12 is 24.

Yes.Two tests for divisibility by 4:If the last two digits are divisible by 4 the whole number is divisible by 4. (In both cases, the last two digits are 52 and 52 is divisible by 4 (52 = 4 x 13), so the original numbers are both divisible by 4.)Add the units digit to twice the tens digit; if this sum is divisible by 4, so is the original number. (In both cases: 2 + 2x5 = 12 which is divisible by 4 (12 = 4 x 3), so the original numbers are both divisible by 4.)

To be divisible by both 4 and 5, the number has to be divisible by 20. Therefore, there are 12 numbers between 1 and 240, inclusive, which are divisible by 4 and 5: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240.

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