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In the word DAUGHTER, there are 3 vowels namely, A, U, and E, and 5 consonants

namely, D, G, H, T, and R.

Number of ways of selecting 2 vowels out of 3 vowels =

Number of ways of selecting 3 consonants out of 5 consonants =

Therefore, number of combinations of 2 vowels and 3 consonants = 3 × 10 = 30

Each of these 30 combinations of 2 vowels and 3 consonants can be arranged among

themselves in 5! ways.

Hence, required number of different words = 30 × 5! = 3600

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Q: How many words with or without meaning each of 2 vowels and 3 consonants can be formed from the letters of the word DAUGHTER?
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