This sounds like my core 2 mathematics from last year, it sounds like a geometric progression. your talking about interest, yes?
3000x1.02^n = 6000
6000/3000 = 2
1.02^n = 2
log (base 1.02) 2 = n
n= 35?
I'm not quite sure if that's right.
Another reply: The exact answer is log(2) / log(1.02) (logarithm in any base, same base for both). Almost exactly 35 years. (1.02 is 1 + 2%). For a quick estimate, divide 70% by the interest rate, in this case, 2% - this gives you 35 years. This is a rough formula, that will fail for higher percentages.
12% of 3000 dollars = 3000*12/100 dollars = 360 dollars.
3000 dollars
$903% of $3000= 3% * $3000= 0.03 * $3000= $90
3000*(7/100)*(6/12) = 105 dollars
100%= $3015%= $30/100 x 15= $4.50
12% of 3000 dollars = 3000*12/100 dollars = 360 dollars.
3000 * .03 = $90
3000 dollars
3000
3000
$903% of $3000= 3% * $3000= 0.03 * $3000= $90
the answer is 2250
10% of $3,000= $300
3000*(7/100)*(6/12) = 105 dollars
To find 10 percent of a number, multiply the number by 0.1. In this instance, 0.1 x 30000 = 3000 dollars.
It's $450 off, $2,550 still on.
100%= $3015%= $30/100 x 15= $4.50