How much heat is required to convert 0.3 kilograms?

Answer 1

That's going to depend on a lot of things that you haven't told us, such as

-- what the 300 grams are made of

(This will tell us the melting and boiling temperatures of the substance, as well as its

latent heats of fusion and vaporization, and its specific heat capacity. We'll need to

know all that stuff to give you an answer)

-- what you want to convert them from and to

-- what their temperature is when you start the process

Answer 2

Measured in joules, this process would require 100,375 J to be accomplished.
336 X 103 X 0.3 J

=336 X 0.3 kJ

= 100.8 kJ

Answer 3

Measured in joules, the process would take 334,584 J to occur completely.

Answer 4

The molar heat of fusion of water in J / g is 334. To find the heat required to convert 0.3 kg, use the equation: heat of fusion * mass = heat required. It would require 100.2 kJ.

Answer 5

The latent heat of fusion of water is 334 J/g. This will take 334x300 or 100200 J to melt the ice. Once it's melted, it's at 0C.

Answer 6

4.16 J/mole;

30g of H2O(s) X (1mol/18.01528g)=1.665253

4.16 J/mole X 1.665253 mole= 6.92752 J in sig figs, 6.9 J

Answer 7

100 kilo joules of of heat are required to change 0.3 kilograms of ice to water.

Answer 8

About 24 Kilo Calories

Answer 9

100,375 J