Assuming standard atmospheric pressure, 2260 kilojoules.
Leaving aside the effects of pressure, yes, the temperatures are the same. But the amount of heat (thermal energy) per gram, is much greater for the steam.
You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state. 2.67 kg = 2670 grams q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C) = - 9.45 X 105 Joules ----------------------------------- This much heat energy must be lost to lower the temperature of the steam.
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
6,520 Btus
All calculations below are assumed done with all materials (ice, water, and steam) being at normal atmospheric pressure. 3.0kg is 3000 gm. Heat required to raise temperature of ice from -10 degree celcius to 0 degrees celcius is 3000 x 10 cals. (A) The latent heat of fusion of ice is 80 cals per gm. So heat needed to melt 3000 gm of ice at 0 degrees celcius is 3000 x 80 cal. (B) The heat required to convert 3000 gms of water from 0 degrees celcius to 100 degrees celcius is 3000 x 100 cals. (C) The latent heat of vaporization of steam is approximately 540 cals per gm. Hence heat required to convert 3000 gms of water to steam at 100 degrees celcius is 3000 x 540 cals. (D) Now add (A) + (B) + (C) + (D) = 30000 + 240000 + 300000 + 1620000 cals. And that is = 2190000 cals = 2.19 X 10 to power 6 cals.
E = m c (delta)T
46389000 j
at 105 degreesCelsius,steam is still steam.at about 50,000 degrees Celsius,steam turns into plasma, the fourth state of matter.
Steam. Water boils at 100 degrees Celsius.
It equals one kilpod.
steam
Yes, it can.
100 degree Celsius
A "steam bath" is a room with super saturated steam at about 50 or 60 degrees Celsius.
Yes, but not at atmospheric pressure (which is the pressure of your kitchen). Steam can be hotter than 100 degrees celsius under pressures higher than this.
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
at 100 degrees liquid water will go to steam and steam will go to liquid water