The average home fluorescent lamp consumes 40W of power. Running for one hour it will consume 0.04 KWh. Units of electricity are charged per Kilowatt hour.
The 100W bulb emits more light energy per second than the 40W bulb, so it appears brighter due to the higher intensity of light. This increase in brightness is a result of the higher power consumption and light output of the 100W bulb compared to the 40W bulb.
40W on a light bulb indicates that the bulb consumes 40 watts of power. This measurement refers to the amount of energy the bulb consumes to produce light. In general, higher wattage bulbs produce more light but also consume more energy.
This is a bit less light than a 40W incandescent bulb (much less than a 9-watt CFL bulb, but twice as much as a 5-watt CFL mini-bulb).
-- The voltage makes no difference. -- The 400W device dissipates ten times as much power as the 40W device does. We don't know how much of each one's power consumption is radiated in the form of heat, UV light, etc. But if the spectral distribution of their output is similar, then the one that dissipates more power produces more visible light, and appears brighter.
40w=.04kWh.04*12 hours=.48 kWh
Joules = watts x seconds. Just convert the minutes to seconds, then multiply.
Yes, your assumption is correct. Lamp fixtures are rated on how well they dissipate the heat given off from an incandescent light bulb. As CFL lamps run much cooler there is no problem using them in the same rated fixture that is incandescent rated.
If you mean the 40 watt light bulb inside, are you sure you are replacing it with a special 40W appliance bulb? A regular bulb will not last long at all inside of a refrigerator.
It's the 40W tube! because it's nonlinear: indeed it generates harmonics which increase the apparent power and thus the apparent energy.
Not very bright at all. A 40W light bulb is about 450 lm, so a 55 lm source would be about 1/8th as intense as a 40W bulb.
75W means bulb which give 75W power when connected to domestic light. Power is nothing but energy per second. Thus energy consumed by bulb can be calculated as follows. E = 75*60*60*4J = 1080kJ