1 2-liter container holds a total of 2 liters of liquid.
To dilute a liquid to 50 percent, you would need to add an equal volume of water to the original liquid volume. For example, to dilute 1 liter of liquid to 50%, you would add 1 liter of water to make a total of 2 liters at 50% concentration.
The amount of heat absorbed by 1 kg of liquid to vaporize it depends on what that liquid is, (water?), and what the temperature of the liquid is at the start of the process. Obviously, it will take more heat to vaporize 1 kg of liquid that is at 0º than it will to vaporize 1 kg of liquid that is at, say, 30º.
The volume of 200 g of liquid would depend on the density of the liquid. For water, which has a density of approximately 1 g/mL, 200 g of water would be equivalent to 200 mL.
First, we need to find the mass of the liquid by subtracting the mass of the empty bottle from the total mass. The mass of the liquid is 5.760g - 4.570g = 1.190g. The density of the liquid is then calculated by dividing the mass of the liquid by its volume: 1.190g / 3.360mL ≈ 0.354 g/mL.
i think approximately 800g of flour fits in a container meant for 1 liter of liquid (water).
38 grams of pop is approximately 1/6 of a cup.
To determine how much liquid needs to be added to reach a total volume of 1 liter, subtract the current volume from 1 liter. For example, if you have 300 milliliters, you would need to add 700 milliliters to reach 1 liter. Simply adjust the amount based on the existing volume to find the correct volume to add.
1
To dilute a liquid to 50 percent, you would need to add an equal volume of water to the original liquid volume. For example, to dilute 1 liter of liquid to 50%, you would add 1 liter of water to make a total of 2 liters at 50% concentration.
about 1 and a 1/4 cups
1 cup
It is 1 teaspoon.
It's precisely 1/4 of a gram.
lf = 3.35 x 105 J kg-1 This much amount of heat required to convert 1 kg of ice to liquid Mani.Ra
925 milliletres
The amount of heat absorbed by 1 kg of liquid to vaporize it depends on what that liquid is, (water?), and what the temperature of the liquid is at the start of the process. Obviously, it will take more heat to vaporize 1 kg of liquid that is at 0º than it will to vaporize 1 kg of liquid that is at, say, 30º.
1 liter