How many liters of water are in a 27 foot round pool X 50 inches deep?

Answer 1

Use formula for volume of cylinder, V=pi x radius squared x depth. Where Pi=3.14, radius= 13.5 feet,and depth= 4 feet. The answer will be in cubic feet. I calculate it to be 2299.06 cubic feet but I'm half asleep. Use various conversion factors to get other volume measures.

For a round above ground pool, the calculation is:

Diameter x Diameter x Depth X 5.9 = Number of Gallons

Please note that the depth is the ACTUAL water depth NOT the height of the pool wall (the water is usually around 6 inchs lower than the wall height).

For your example:

For a 27-foot round pool with a actual water depth of 3.5 ft: 27x27x3.5x5.9 = 15,054 or around 15,000 gallons.

Hope this helps ...

http://www.poolspa.com/calculator/

Answer 2

In order to calculate the capacity, we need to find the surface area. To do that,

I'd have to know what "a 27 foot pool" means. Is it a square with 27-ft sides ?

Is it a circle with 27-ft diameter ? 27-ft radius ? Is it a rectangle with 27-ft length

and unknown width ? An ellipse with eccentricity 0.1 and a 27-ft semi-major axis ?

Each possibility would produce a different capacity.

Answer 3

(area of a disc) x ( depth of cylinder) = volume of cylinder area circle = (pi) x (radius2) You'll need to convert the imperial measurements into metric ones.

Answer 4

If the bottom is flat and level, then 67.32 gallons for every inch that the water is deep.