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How much water does a hose that is 1 inches in diameter times 4000 feet?
Wiki User
∙ 14y ago
The volume of the hose is L x Pi x r2 where L = length (4,000 ft) and r = radius = 1/2 inch = 1/24 foot, thus the volume of water it holds is 4,000 x 3.14159 x (1/24)2 = 21.8 cubic feet
Wiki User
∙ 14y ago
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If you have 4000 linear feet of 8 inch water pipe how much water will it hold full?
Assuming: an 8 inch inside diameter, 1 gallon of water weighs 8.345404 pounds, 231 cubic inches of water to the gallon, volume of cylinder = Pi * radius^2 * height volume=3.14 * 4^2 * (4000 * 12) volume = 3.14 * 16 * 48,000 = 2,411,520 cubic inches 2,411,520 cubic inches of water when full. -------------------------------------------------------------------------- A 4000 foot cylinder/pipe with an 8 inch inside diameter, if full of water, will contain 10,439.48 gallons of water weighing a total of 87,121.68 pounds or 43.56 tons.
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What times what times 3.2 equals 4000?
How about: 1*1250*3.2 = 4000
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4,000 inches=333.333333 feet
