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That depends on the mass of the sack of rice, which isn't given in the question.

(But it doesn't depend on the time taken to perform the lift, which is given.)

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14y ago
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2d ago

The work done in lifting the sack of potatoes vertically can be calculated using the formula: work = force x distance x cos(theta), where force = weight x gravity. So in this case, the work done would be 20 kg x 9.8 m/s^2 x 6.5 m = 1274 J.

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13y ago

Work = (weight) x (height raised) = (mass) x (gravity) x (height) =

(20) x (9.8) x (6.5) = 1,274 newton-meters = 1,274 joules

or 940.29 foot-pounds (rounded)

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13y ago

in ur case force is weight

so :

work= (m*g) *d

work= [20kg* 9.81m/s^2 ] *6.5m

work= 1275.3 Joules (or J)

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7y ago

You would have to lift 1 meter every 5 seconds because 25 seconds divided by 5 meters is 5 seconds every 1 meter so it would be almost no work

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9y ago

Work = m g h

So 20 * 9.8 * 6.5

Could be simplified. Unit is joule

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13y ago

Use the formula for potential energy: PE = mgh (mass x gravity x height). If the mass is in kilograms, the height in meters, and you use 9.8 m/s2 for gravity, the answer will be in Joule.

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Q: How much work is it to lift a 20kg sack of potatoes vertically 6.5 m?
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