force x distance
force=9800n
distance=250m
9800 x 250= 2450000 Mega Joutes
2
11,000/20=550newtons
24000 joules
500 Joule.
Without knowing the mass of the block that cannot be calculated.
2
11,000/20=550newtons
11,000/20=550newtons
11,000/20=550newtons
24000 joules
WORKAn engine is used to lift a beam weighing 9800 n up to 145 m how much work must the engine do to lift this beam?Solution1.This is what you know:force: F =9800 n distance: d =145 m2.This is what you need to find out:work: W = ? J3.This is the procedure you need to use:Substitute the known values f= 9800 n and d = 145 m into the work equation:W = Fd = (9800 N)(145 m) = N·m = 1421000 J4.Check your answer:Check your answer by dividing the work you calculated by the distance given in the problem. The result should be the force given in the problem.
500 Joule.
The Beam bridge costs less. And much, much smaller. The Beam bridge costs less. And much, much smaller.
work done=m*g*h=53*9.81*7=3.63951 kJ where: m is mass (kg) g is acceleration due to gravity h is lift displacement
Without knowing the mass of the block that cannot be calculated.
98 j
10 J (novanet)