Well it is according to faraday's laws of electromagnetic induction. Whenever a coil rotates in a magnetic field,magnetic flux passing through the coil will get changed, and faradays first law states that whenever there is a change in magnetic flux linked with the coil, a emf is induced in it. So due to this emf bulb will light up. Well if you want the change in flux to be explained in more general way I can explain it like this: Suppose it is raining and you have kept a bucket to accumulate the rain water in it. Initially keep the bucket vertical, so maximum amount of rain water will drop into bucket. Now start tilting the bucket, the waterdrops entering the bucket will start decreasing. now make the bucket horizontal, so now no drop will enter into the bucket. So number of water drops entering the bucket depends on inclination of bucket. Here rainddrop is similar to magnetic flux and bucket is similar to coil. So as you rotate the coil, flux linked with the coil changes.
To limit the current through the lamp when the gas ionises and conducts.
Assuming that the voltage rating of the lamp matches the rated secondary voltage of the transformer, the lamp will operate at its rated power.
when the coil wire in the bulb has electricity passing through it the wire heats up to then create light.
Both are acceptable with different meaning. I read by the light of the lamp means I use the lamp to light the pages so that I can read them. I saw it in the light of the lamp means it was visible in that pool of light caused by the lamp.
Because the electrons flow in almost negligible time.
Mostly heat, but that heat causes a filament to glow, which makes light.
Yes,without a working coil the engine will not get fire to the spark plugs you can check your coil by using a 12 volt test lamp ground the black wire and connect other lead to negative side of coil, if the light does not flicker when turning the motor over your coil needs replaced
When two light bulbs are connected in series , there is voltage drop which causes the second lamp to dimAnswerWhen two lamps are connected in series, neither lamp will be subject to its rated voltage and, so, each lamp will be dim. Surprisingly, perhaps, the lamp with the higher power will be dimmer than the lamp with the lower power!
A fluorescent lamp or fluorescent tube is a gas-discharge lamp that uses electricity to excite mercury vapor. The excited mercury atoms produce short-wave ultraviolet light that then causes a phosphor to fluoresce, producing visible light. A fluorescent lamp converts electrical power into useful light more efficiently than an incandescent lamp. Lower energy cost typically offsets the higher initial cost of the lamp. The lamp fixture is more costly because it requires a ballast to regulate the current through the lamp.
A fluorescent lamp or fluorescent tube is a gas-discharge lamp that uses electricity to excite mercury vapor. The excited mercury atoms produce short-wave ultraviolet light that then causes a phosphor to fluoresce, producing visible light. A fluorescent lamp converts electrical power into useful light more efficiently than an incandescent lamp. Lower energy cost typically offsets the higher initial cost of the lamp. The lamp is more costly because it requires a ballast to regulate the flow of current through the lamp.
The relay is used to "interlock" a circuit. It consists of a coil and a number of auxiliary "normally open" or "normally closed" contacts. A limiting condition is wired through the coil contacts and resulting conditions are wired through the auxiliary contacts. When the limiting condition is met, the coil will pull in and change the state of the auxiliary contacts. For example, if you want a lamp (lamp 1) to turn off when a second lamp (lamp 2) is turned on, lamp 1 would be wired through a "normally closed" set of contacts and lamp 2 would be wired through the coil contacts. When lamp 2 is turned on, the coil will pull in and open the "normally closed" contact for lamp 1, turning it off.
When a lamp is turned on in a dark room, firstelectric energy turns into lightenergy, which allows us to see, then becomes thermal energy, which causes the to bulb be hot.
Your on a ball (the earth), rotating in front of a lamp ( the sun)
A flourescent lamp is a gas-discharge lamp that uses electricity to excite mercury vapor in argon or neon gas, resulting in a plasma that produces short-wave ultraviolet light. This light then causes a phosphor to fluoresce, producing visible light.
Generally assume it's the coil as that device runs hot and at very high voltages. Take a small 12V DC light, solder some wires to it. Connect one lead of the lamp to the coil low voltage lead going to the coil. Connect the other side to ground and crank the engine. If the lamp flickers or flashes it's a bad coil. If the lamp stays on put the ungrounded lead on the other low voltage post and re-test. If it flashes then its the coil, still no flash at crank and it's the pickup.
The plural for lamp is lamps.
Technically, no. The lightbulb in the lamp emits light, not the lamp itself.
A light bulb (called a lamp by the industry) will emit light when a voltage is applied to it. The applied voltage causes current flow through the lamp, and the lamp responds by emitting light. (There are many different lamps and they work differently, and we're generalizing here.) The lamp doesn't care whether the voltage that drive current through it comes from. It responds to the voltage (and current flow) according to its rating. If a given voltage is nominal for a lamp under inspection and we apply that, that lamp can be powered up by a generator, a battery, solar cells, or a number of other sources. Apply the appropriate voltage, and the lamp responds.
No, one should be positive and the other would be grounded through the electronics. If your testing the leads with a test lamp both sides will light up the test light because one side is hot and the other side you are providing the ground with the test lamp causing the light to illuminate.
A fluorescent light bulb contains a low pressure mercury vapor gas-discharge lamp. This lamp produces visible light by sending electrical current through the mercury vapor and energizing the molecules. This produces ultraviolet light that causes a phosphor coating on the bulb to glow.
The light bulb is inside the lamp base, right?so, when you turn on the lamp, the light shines THROUGH the lamp base, although dimmer, so you can se both. if you took the lamp base off, the light bulb would look brighter.
The light is getting dim because the choke is using the energy the lamp should be using. The purpose of the choke is to remove transients; if it is using power at 50 or 60Hz, this is not desirable. My guess is this lamp is using a new energy efficient (not incandescent) light bulb? If this is the case, don't. If this is a choke you added to the lamp, then perhaps it's the wrong type choke (too large inductance). If you added this, it could be that you inadvertently inserted resistance in the lamp wire. Check to make sure nothing is getting hot around your new wiring. A bad solder point could cause this to some degree.
the 1989 Honda accord lxi has a brake lamp light on the dashboard, if the brake lamp light is on, this means you have a brake/tail light out or disconnected
incandescent lamp helogen lamp fluorescent lamp led lamp neon lamp
Electrical energy absorbed by the lamp's filament produces thermal energy as well as light.