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Example 1: There are 5 gene pairs, how many gametes can be formed if only 3 of them are heterozygous?

There are two ways you can work out this problem, it depends on the genotype and phenotype. As you calculate the genotype you take 2 and raise it to the number of heterozygous gene pairs, which in our case is 3; so it would read, 2^3=8 different gametes. If we took the phenotype you would take the inverse of 2 and raise it to the number of heterozygous gene pairs which is 3; so it would read 1/2^3 which equals 1/8=0.125 different gametes

dilse2 said ....................................................

Number all probable gametes = 2n x m

where

n = number of heterozygous allele pairs

m = number of homozygous allele pairs

for your question

n = 3

m = 2

Number all probable gametes = 23 x 2 = 16

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14y ago

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