Find an electron dot diagram for nA2O?

Answer 1

i think it's meant to be NO4 3- .. an ion because it's NO2 - and NO3 2-

but then i don't know how they're actually bonded! i guess there's deffo one dative bond between N and O and then either 3 dot cross ones ..or another dative from n to o and one from an o to n and one dot cross! but i expect it's three dot crosses and one dative! because it's more even.. probs.

guut luck anyway :D i think it's meant to be NO4 3- .. an ion because it's NO2 - and NO3 2-

but then i don't know how they're actually bonded! i guess there's deffo one dative bond between N and O and then either 3 dot cross ones ..or another dative from n to o and one from an o to n and one dot cross! but i expect it's three dot crosses and one dative! because it's more even.. probs.

guut luck anyway :D

Answer 2

1S2 2S2 2P3

so 1S2 2S2 2Px1 2Py1 2Pz1 (in a different form)

For all the exited cases i have seen only 1 electron jumps, though for higher level chem this may not be the case.

So exited it would be 1S2 2S2 2P2 3S1

or 1S2 2S2 2Px1 2Py1 3S1 (it is a "lower level" chem convention to fill up the x then y then z though in nature this may not happen the only rule is that you can not put 2 electrons in one say x before the y and z have at least one electron in them)

as for drawing

this is a drawing of electron configurations for the 3D level so say to fill up 3Dxy with one electron you'd just draw one of the ballon looking things

no idea why you would have to draw excied elements though

if some one could find a picture of the S and P orbitals thx.

Answer 3

hey, recently studied this myself in GCSE Chemistry and it's pretty simple in any situation once you know what you're doing:

Both elements have 2 electrons in their inner shells, of course, so ignore those.

Nitrogen has 5 electrons in its outer shell, and so each nitrogen atom needs 3 electrons from the oxygen atom to obtain a full outer shell.

The oxygen atom has 6 electrons in its outer shell, and so it needs one electron from each of the Nitrogen atoms in order to obtain a full outer shell.

so: each Nitrogen atom is sharing one electron, and being given three from the oxygen.

In order to draw this, the Oxygen atom goes in the middle of the two nitrogen atoms (as I'm sure you know). The oxygen has 6 electrons to be shared between two nitrogen atoms (each of which requires 3), so the electrons on the outer shell of the oxygen must be split between each of the overlapping outer shells (i.e, three on the overlap of one of the nitrogen atoms, and three on the other). On this overlap, from each Nitrogen atom there must be one electron, with the remaining 4 being placed anywhere on the outer shell that isn't overlapping the oxygen.

So, thinking of oxygen's electrons as X's, and Nitrogen electrons as O's, the distribution should be:

1st Nitrogen outer shell: 4 O's

1st Nitrogen/Oxygen overlap: 3 X's, one O

Oxygen: None

2nd Nitrogen/Oxygen overlap: 3 X's, one O

2nd Nitrogen: 4 O's

If you don't understand what i mean by the overlap, I'm referring to the point at which the two outer shells meet. Because there will be 4 electrons drawn on each, you may have to make the overlap pretty big, so that it's clear what you mean. The atom doesn't have to be drawn as a perfect circle so, if each of the atoms is shaped like an oval in order to make these overlaps big enough to fit 4 X's and O's on, that's fine.

sorry for the complicated explanation, to be honest it's a pretty hard thing to explain without the use of some sort of diagram

hope this helped :) If you need any help with any other problems, feel free to contact me at Biggles99@hotmail.com, by e-mail or msn messenger.

Answer 4

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o : : c : : o

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Answer 5

1s2 2s2 2p3

(first shell: 2 electrons; second shell: 5 electrons)

Answer 6

Nitrogen is in Group 15, so each atom has five valence electrons.

The electron dot diagram for each nitrogen atom would look like this: