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I assume you mean 0,2 M (0,2 mole/dm3). Say we have a volume of 1 dm3, since you didn't specify that in your question.
MHCl=35,5+1,01 g/mole = 36,51 g/mole
nHCl=C/V
nHCl=(0,2 moles/dm3)/1 dm3 = 0,2 moles
mHCl=M/n
mHCl=(36,51 g/mole)/0,2 moles
mHCl=182,55 gram.
The reaction formula: H2 (g)+ Cl2 (g) --> 2 HCl (aq)
Now that you know how that you get 2 moles of HCl by the reaction, then you need to calculate how much H2 and Cl2 you need for the reaction. Remember that the mass we get from this reaction is 2 moles x 182,55 g/moles = 365,10 gram. That means we need to use a lot of gas when we lead it down in the specified volume of water to form a solution of HCl. Then only use half as much volume of this solution to get the desired concentration of 0,2 M HCl.
It is easier if you have the salt HCl (s), then you only take 182,55 gram of the salt and solve it in a volume of destilled water that is not 1 dm3, but a little less, since the solution might change the density, thus exceeding 1 dm3.
Then, when you have dissolved all the solid salt to ions in the solution, you can fill up to the specified volume of 1 dm3.
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∙ 11y ago
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What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
25 mL
How do you prepare 10mM solution of Tris-HCl?
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Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
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