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How is instantaneous acceleration related to a velocity-time graph?
Acceleration is the derivative of velocity (a=dv/dt). If you are not familiar with calculus then it would be sufficient to say that the slope of the line tangent to the graph, only touches at one point, is equal to the instantaneous acceleration.
What interpretation can you derive regarding the motion from the graph of instantaneous speed vs time graph?
At least two things regarding the motion can be interpreted from the graph of speed versus time.The slope of the graph represents the acceleration of the thing being charted.And the net area under the graph represents the position of the thing being charted.Each of these graphed as they change with time, on the same time scale as the original graph or some other one if more convenient.
Which line segments on a velocity versus time graph is physically impossible?
A physically impossible line segment on a velocity vs. time graph would be one with a horizontal slope, indicating constant acceleration. This would violate the laws of physics, as constant acceleration requires a non-zero force. Similarly, a vertical line segment would represent an instantaneous change in velocity, which is also physically impossible as it would require infinite acceleration.
What graph of acceleration vs time constant velocity?
When the acceleration of a particle is constant, the velocity will be increasing at a constant rate. This means that the velocity versus time graph will appear with a straight line "slanting up to the right" in the first quadrant. With time on the x-axis and velocity of the y-axis, as time increases, velocity will increase. That means the line will have a positive slope. The higher the (constant) acceleration, the greater the slope of the line. If we take just one example and mark equal units off on our axes, and then assign seconds along the x-axis and meters per second along the y-axis, we can plot a graph for an acceleration of, say, one meter per second per second. Start at (0,0) and at the end of one second, the velocity will be one m/sec. That point will be (1,1). After another second, the velocity will be 2 m/sec owing to that 1m/sec2 rate of acceleration, and that point will be (2,2). The slope of the line is 1, which is the rate of acceleration.
Name the two physical quantities which can be obtained from the velocity-time graph?
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
How can one determine acceleration from a distance-time graph?
To determine acceleration from a distance-time graph, calculate the slope of the graph at a specific point. The steeper the slope, the greater the acceleration. The formula for acceleration is acceleration change in velocity / time.
How can one determine velocity from an acceleration-time graph?
To determine velocity from an acceleration-time graph, you can find the area under the curve of the graph. This area represents the change in velocity over time. By calculating this area, you can determine the velocity at any given point on the graph.
How can one determine the average acceleration from a position-time graph?
To determine the average acceleration from a position-time graph, you can calculate the slope of the line connecting the initial and final velocity points on the graph. This slope represents the average acceleration over that time interval.
How can one determine the average acceleration from a velocity-time graph?
To determine the average acceleration from a velocity-time graph, you can calculate the slope of the line connecting the initial and final velocity points on the graph. This slope represents the average acceleration over that time interval.
What graph would you use to determine a persons height?
You would not use a graph to determine one person's height at a single point in time. You could use a line graph to track the height of a person over time. You could use a histogram to determine the heights of lots of people at one time.
The slope of velocity versus time graph gives?
If your graph shows velocity on the vertical axis and time on the horizontal axis, then the slope of the graph represents the acceleration. More specifically, the slope of the graph at a specific point represents the acceleration at that instantaneous point in time. So if the slope of the graph doesn't change (i.e. the graph is a straight line), then the acceleration is constant and doesn't change over time. In calculus, this is represented as the derivative: The derivative of velocity with respect to time equals the acceleration.
How can one learn to find kinematic variables from a graph of position vs. time?
To find kinematic variables from a graph of position vs. time, one can calculate velocity by finding the slope of the graph at a specific point, and acceleration by finding the slope of the velocity vs. time graph. Additionally, one can determine displacement by finding the area under the velocity vs. time graph.
The speed of a car moving with constant speed equals the slope of the line representing the cars motion on a distance time graph?
acceleration A motion such as the one above further illustrates the important principle: the slope of the line on a velocity-time graph is equal to the acceleration of the object. This principle can be used for all velocity time to determine the numerical value of the acceleration.
How is instantaneous acceleration related to a velocity-time graph?
Acceleration is the derivative of velocity (a=dv/dt). If you are not familiar with calculus then it would be sufficient to say that the slope of the line tangent to the graph, only touches at one point, is equal to the instantaneous acceleration.
How can one determine the wavelength from a graph?
To determine the wavelength from a graph, you can measure the distance between two consecutive peaks or troughs on the graph. This distance represents one full wavelength.
What can you calculate from velocity time graph?
From a velocity-time graph, you can calculate the acceleration by finding the slope of the graph at a certain point. The area under the graph represents the displacement of the object. You can also determine the direction of motion based on the slope of the graph (positive slope indicates motion in one direction, negative slope indicates motion in the opposite direction).
How can one determine the initial value on a graph?
To determine the initial value on a graph, look for the point where the graph intersects the y-axis. This point represents the initial value or starting point of the graph.
