If it is distance from a point versus time, with distance on the vertical axis and time on the horizontal axis, it would show a steep vertical climb on the graph. The steeper vertical change, the faster, but never completely vertical. Large "rise" (distance) over short "run" (time). With 0 acceleration, the graph is a straight line.
Slope of speed vs time graph = acceleration.
Im guessing that this is a distance over time graph. if so, the gradient of the line of best fit would have a low value. (not be very steep)
The slope of a speed/time graph at any point is the acceleration at that instant.
The slope of a velocity-time graph represents acceleration.
The slope of the graph of speed vs time at each point isthe magnitude of the acceleration at that point in time.
Negative slope on a speed/time graph indicates decreasing speed. (Some call it "deceleration", although I wish they wouldn't.)
The angle of the graphed slope changes with changes in speed.
Im guessing that this is a distance over time graph. if so, the gradient of the line of best fit would have a low value. (not be very steep)
Im guessing that this is a distance over time graph. if so, the gradient of the line of best fit would have a low value. (not be very steep)
No. The slope on a speed vs time graph tells the acceleration.
The slope of the speed-vs-time graph is the magnitude of acceleration.
A graph requires two numerical variables before it can have a meaningful slope. A distance-graph has only one variable so it does ot have a slope in any meaningful way. For eaxmple, you could have a graph showing the distances of varoius places from, say London.
acceleration
If the slope is 'uphill' then the car is going faster
Acceleration is how fast you get up to speed.
The slope of a speed/time graph at any point is the acceleration at that instant.
Speed can be shown on a graph of position versus time, and acceleration can be shown on a graph of speed versus time.
The slope of a velocity-time graph represents acceleration.