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The valence electron configuration of Cr is 3d5 4s1 , whereas it should be 3d4 4s2 but it is not like that because there is more stability of the element if it is like 3d5 4s1 as 5 orbitals of d subshell and 1 orbital of s subshell are singly filled means there is one electron in each orbital and it is stable. But if it would have like 3d4 4s2 then there would be 4 orbitls of d subshell filled and one would be empty and not much stable, so one electron from 4s jumps to 3d to fill that empty orbital and make it more stable. So its full configuration is 1s2 2s2 2p6 3s2 3p6 4s1 3d5. If u have any more confusion about orbitals, configuration etc. tell me.

Added:

Oxidation state (possibilities) +6, 5, 4, 3, 2, 1, -1, -2.

Valence electrons (transition group no.6, [Ar]4s13d5)

[1s2 2s2 2p6 3s2 3p6] 4s1 3d5

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