3,612,345,678
There are ten thousand possible pin numbers with four digits. To generate your list, start at 0000 and start counting, to 9999.
1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
No, counting numbers you can ignore or say they have an infinate number of significant digits. By counting numbers I mean things you count, or non measurements, or numbers you wouldn't round to significant digits anyway . Measurements always have significant digits.
155
One million is 1 followed by 6 zeroes - a total of 7 digits.
Both digits are successive counting numbers.
The 3-digit numbers are all the counting numbers from 100 to 999.That's (the first 999 counting numbers) minus (the first 99 of them).There are 900 of them.
Counting all integers from 1 to 238 inclusive, there are 606 digits between these two numbers.
Write the digits in such a way that there are six digits to the right of the number of millions, and three digits to the right of the thousands. Fill out missing digits with zeros.
I believe there would be a total of 1,000 combinations possible, if you're counting 000-999. If you're only counting whole numbers 100 and up (numbers in the hundreds) I think there are 900.
We have ten fingers (including thumbs) and early counting is based on one-to-one mapping onto these digits. So one reason is simple familiarity. The other advantage of counting in decimals is that fewer digits are required: 4 decimal digits takes you to over a thousand, you would need 10 binary digits to go over 1024. It gets worse with larger numbers: 7 decimal digits to go over a million but 20 binary digit. I have phones with 11 digit numbers (without the international country code). In binary, that would be a 33-digit number. No thanks!
Three. Significant figures (or numbers) are determined by counting how many digits above zero appear in a number.