The answer is a number N of the form N = 4k1 + 2 = 5k2 + 1 where k1 and k2 are integers. The first few numbers that fit N = 4k1 + 2 are 2,6,10,14,18,22,26,30,34,38,42,46 By inspection we can see that the smallest solution for N is 26. Adding 20 gives another solution - 46 - which works because 20 is the lowest common multiple of 4 and 5. Any multiple of twenty, plus six, will be a solution.
A dime is worth 10 cents each, or $0.10. This means that there are 10 dimes in a dollar. If these dimes are split into two equal groups, then 10/2 = 5 dimes per group.
two1.00/0.10 = 1010/5 = 2
20 dimes = 2.00 20 nickels = 1.00 Total = 3.00
20 dimes
rolled coins - pennies and dimes...
A dime is worth 10 cents each, or $0.10. This means that there are 10 dimes in a dollar. If these dimes are split into two equal groups, then 10/2 = 5 dimes per group.
2
two1.00/0.10 = 1010/5 = 2
The X.X1 at the end of the number implies that there could be 1, 11, 21, 31, etc. pennies. Now, we could go through and test the instances. .01 means that there is 1 penny. Therefore, there are 2 dimes to make .31, which does not work. .11 means that there are 11 pennies. Therefore, 22 dimes are required, which make $2.31. This works, so there are 22 dimes.
A 10 dimes and 30 nickels b 21 dimes and 19 nickels c 19 dimes and 21 nickels d20 dimes and 20 nickels
20 dimes = 2.00 20 nickels = 1.00 Total = 3.00
20 dimes
Let N be the number of nickels. The value of nickels is 0.05N and the value of dimes is 0.10(2N-12). We can form the equation 0.05N + 0.10(2N-12) = 2.55 and solve for N. After solving, we find that there are 9 nickels.
Ten it each group.
rolled coins - pennies and dimes...
1700 = $170.00 I just counted them today!!!!
That depends on the 'unit' of the 5,000 number in the question. -- 5,000 dimes make 5,000 dimes. -- 2,500 dimes make 5,000 nickels -- 500 dimes make 5,000 pennies -- 12,500 dimes makes 5,000 quarters -- 50,000 dimes makes 5,000 dollars