One chance in 6.
Rolling the dice once will result in any one of the six numbers having the same probability of being up. The probability of getting a '5' = 1/6, the same as getting a '1.' ============================
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.
The probability of rolling two 6-sided dice and getting the same number on each is 1/32, or "one out of thirty two". This is because there are 6 oppurtunities on each dice, and the probability of getting the same of the 6 oppurtunites on two dice is 6 squared, which is 32.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
Pr(Two different numbers) = 1 - Pr(Two same) = 1 - 1/6 = 5/6 = 83.3%
The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.
Rolling the dice once will result in any one of the six numbers having the same probability of being up. The probability of getting a '5' = 1/6, the same as getting a '1.' ============================
I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?" To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.
The probability of rolling two 6-sided dice and getting the same number on each is 1/32, or "one out of thirty two". This is because there are 6 oppurtunities on each dice, and the probability of getting the same of the 6 oppurtunites on two dice is 6 squared, which is 32.
The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
Pr(Two different numbers) = 1 - Pr(Two same) = 1 - 1/6 = 5/6 = 83.3%
The probability of rolling the same number on five dice is (1/6)4, or about 0.0007716.
Each face of the dice has the same probability so each side has 1/6 probability
If it is a regular dice then the probability is 3/6 that is 1/2
Probability is 1/8 or 0.125 or 12.5% Explanation: A fair dice with six sides (numbers) has a probability of 1/2 of rolling an even number. Note: 1/2 = 3/6, where the dice has 3 even numbers out of six total sides. The probability of three same dice all roll an even number is the probability of one of these (1/2) to the power 3, or (1/2) * (1/2) * (1/2) which equals 1/8.
(probably but very unlikely) ----------------------------------- A better answer would be as follows. Throw the first dice. It does not matter which number turns up. Let's suppose it was a 2; Now there is only one 2 out of six different numbers when you throw the second dice. So the probability of scoring another 2 is 1 out of 6 = 1/6 Now for each of the results from the two dice which we have read there is only one 2 from the 6 possible numbers, which again means a probability of 1 out of six = 1/6 So the final probability is found by multiplying 1 (certainty) for the first dice by 1/6 for the second dice by 1/6 for the third dice, which = 1/36
Assuming they are fair, regular dice, the probability is 1/18.