In theory, the effectiveness of the cooling process depends on the ability/capacity of the cooling element (in this case, water and ice) to absorb energy from the system, until the system goes to equilibrium.
Ice is more effective than water in cooling liquids because ice needs additional energy to convert itself to water at 0ºC. Thus, it absorbs more heat from the liquid system it is in, making the liquid system cooler. In other words, ice at 0ºC is simply a "level" higher than water at 0ºC. The additional energy requirement is called "enthalpy of fusion.
Simple mathematical illustration:
X = Y + c
where:
X = energy that ice at 0ºC can absorb until equilibrium
Y = energy that water at 0ºC can absorb until equilibrium
c = constant (enthalpy of fusion)
Step by step mechanism is:
1. Ice at negative degrees Celsius absorbs energy to make the ice temperature 0ºC
2. Ice at 0ºC abosrbs energy to convert the ice to water (still at 0ºC)
3. Water at 0ºC absorbs energy until the system reaches equilibrium
Ice at 0ºC starts on step 2 while water at 0ºC starts on step 3.. Hope it can be of help..
Yes, becasue of the latent heat, which is approx 80 cals per gram.
Water at 0 oC is ice.
At normal (standard) pressure (100kP) water evaporates at 100 Degrees Celsius.
yes (that didn't answer my question.)
It is a solid
Yes, becasue of the latent heat, which is approx 80 cals per gram.
Water at 0 oC is ice.
about one gr per cubic centimeter
To lower the temperature of 1 gram of water by 1 degree Celsius would be to remove 1 calorie.
55 degrees celsius
The boiling point of water is 100 degree celsius. Therefore water changes in to vapor after 100 degree celsius. Therefore the physical state of water at 250 degree celsius is "Gas".
Water freezes at 0 degree Celsius
water at 250 degree Celsius exists in gaseous state
100 degrees celsius
At normal (standard) pressure (100kP) water evaporates at 100 Degrees Celsius.
It is not.
boil it at 100 degree Celsius or freeze it at 0 degree Celsius