job is 50 man days, so 2½ men in 20 days but you can't get half a man, (unless he only works for 20 half-days), so 3 men for 10 days and 2 men for the other 10.
225 days
260 days.
A does 1/10 per day on his own, so in 6 days he's done 60%, leaving 40% done by B in 6 days. B will take 6 x 100/40 days on his own, ie 15 days
For many people, Friday, Saturday, and Sunday are the special days of the week, because Saturday and Sunday are the weekend, when they have time off, and Friday is the day before the weekend, so in a sense, when they finish work (or school) on Friday, their weekend begins.
7 days in a week
225 days
6
12 days
If a "certain number of men" less 10 takes 20 days (twice as long) to finish the piece of work, then the "certain number of men" who can finish the work in 10 days would 20. If it takes 10 men less twice as long to do the work, then twice 10 men (20) can finish the job in 10 days.
Use ratios, 20/15 = 25/x Multiply 15 by 20, then divide by 25. So 25 men could finish a job in 12 days.
have focus & concentrate the work.
7 calender
There are between 160 and 184 work hours in a month, depending on how many work days occur within the month.
Stop posting questions on the internet and get to work. =)
After 20 days. Full solution
10
A does 1/6 of the work in 1 day. B does 1/4 of the work in 1 day. Assuming there is no synergy, A and B, together do 1/6 + 1/4 = 5/12 of the work in 1 day A worked for 2 days so completed 2*(1/6) = 1/3 of the work. So 2/3 of the work remained to be done by A and B together. They would do it in (2/3) / (5/12) = (2/3) * (12/5) =24/15 = 8/5 = 1.6 days. The total time to finish the work is 2 days + 1.6 days = 3.6 days.