Elements and Compounds

If 17.2 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution what is the molar concentration of the ammonia?

Answer

Wiki User
10/04/2010

MV=MV

(17.2mL)(.800M)=M(5.00mL)

2.752 M

2.75 M when you round to the correct amount of significant figures (three)