Magnitude of average acceleration = (change of speed) divided by (time for the change)
Average 'A' = (35 - 65) / 10 = -30/10 = -3.5 meters per second2
-- That's the average over the 10 seconds. We don't know anything about the
value of the acceleration at any particular instant during the 10 seconds.
-- We're working entirely with scalars ... speed, not velocity, and magnitude of
acceleration ... since we don't know anything about the arrow's direction at any
time during the whole event.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
a = m/s/s a = 560/1/7 a = 80m/s/s
You use it when throwing an object at a target. Over any but a trivially short distance, gravity will pull the object downwards. So you aim higher than the target. To hit the target, the vector sum of the initial velocity and the downward acceleration experienced during the flight must be a vector aimed directly at the target.
There is no way to tell unless a height is specified. Once you have that, you would divide the distance (height) by the time (2.5). Suppose 50 feet, and it took 5 seconds to reach that height. You would have 50/5 = 10 feet per second. given the acceleration of gravity is 9.81m/s2 and y=at2 then ymax = 9.81(2.5)2 OR 61.3125m At its highest point it has a velocity of zero. if 0=v0-at and a=9.81 and t=2.5 then v0 = 9.81(2.5) = 24.525 m/s
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
If you're willing to ignore the effect of air resistance, then the answer is as follows: The object's horizontal velocity remains constant (at least until it eventually hits the ground). The vertical component of the object's initial velocity ... call it V(i) ... is the (total initial velocity) multipled by the (sine of the initial angle above the horizontal). Beginning at the time of the toss, the magnitude of the vertical component of velocity is V = V(i) - 1/2gT2. T = number of seconds after the toss g = acceleration of gravity = approx 32 ft/sec2 or 9.8 m/sec2
Use the equation v= u + at where v= final velocity, u= initial velocity, a= acceleration and t= time. Here the inital velocity; u is 0 km/ hr because the plane started from rest; the acceleration, a is 1000 km/ hr; time, t is 1.5 seconds which could be converted to hours to make the solution simpler (1.5 seconds= 1.5/3600 hours). Using the equation v= u +at, v= (o km/hr) + (1000 km/hr)(1.5/3600 hours) v= 0 + (1500/3600) km/ hour v= 0.42 km/ hour
The acceleration of the ball (after it leaves the thrower's hand) is the acceleration due to gravity, g.1 The vertical velocity of the ball at its apex is zero. The horizontal velocity is constant throughout the ball's flight; it is whatever it was at the outset of its arc.2 ---------------- 1. The acceleration due to gravity, g, is -9.8 m/s2 or -32.2 ft/s2. 2. Ignoring the effects of air resistance, which tend to slow things down.
To come to rest, its velocity must change, therefore it will accelerate. Once it is at rest, if it remains at rest, it will no longer accelerate, i.e., its acceleration will be zero.
The acceleration of gravity is [9.8 meters per second2] directed downward.After two seconds of vertical flight, the upward speed of the arrow is (9.8 x 2) = 19.6 m/sless than its initial velocity.Average speed = 1/2 (Vi + Vf) = 1/2 (Vi + Vi-19.6) = Vi - 9.8Distance = (average speed) x (time) = 33(Vi - 9.8) x (2) = 33Vi - 9.8 = 16.5Vi = 16.5 + 9.8 = 26.3 m/s
There is no need to buy Microsoft Flight Simulator X: Deluxe Edition as Microsoft Flight Simulator X: Acceleration contains everything from Microsoft Flight Simulator X: Deluxe Edition and more.
IN flight sim the Flight Acceleration mode is used to make the game move faster (similar to fast forward) This is ok in the normal flight mode but is NOT acceptable in the multi flight i.e. on IVAO etc
13 seconds thats not what i call a flight : )
Since the velocity of an object is composed of its speed and its direction, then an object under the influence of Earth's gravity will always be changing velocity. If it is near the surface, its speed is slowing down if it is moving vertically up, or speeding up if it is moving vertically down. If it is moving horizontally, its speed is slowing because of air friction. But even when it is in a circular orbit and its speed is not changing, the direction in which it is moving is constantly changing. so its velocity is constantly changing. Since we have no information on what the flight is, there is no useful answer.
The average speed is 16.66... (repeating) metres per second. It is not possible to calculate the average velocity without further information because, due to gravity, the velocity is changing continuously during the ball's flight.
It takes the bullet (500/200) = 2.5 seconds of horizontal flight to reach the target.Under the influence of gravity for 2.5 seconds, ignoring air resistance, it will fall(1/2 G) (t)2 = (5) (6.25) = 31.25 meters