1/2 apex
It does not matter what each prior flip's result was. Each flip has a probability of 0.5 heads or tails. Coins do not have "memory".
The probability that the second coin matches the first is 0.5 .The probability that the third coin matches the first is 0.5 .The probability that the second and third coins both match the first is (0.5 x 0.5) = 0.25 = 25%
The probability is always 50/50 even if you flipped 100 or 1000000 coins.
The probability of tossing two coins that are different is 1 in 2, or 0.5.The probability of tossing something on the first coin is 1. The probability of not matching that on the second coin is 0.5. Multiply 1 and 0.5 together, and you get 0.5.
The conditional probability is 1/4.
No, two events are independent if the outcome of one does not affect the outcome of the other. They may or may not have the same probability. Flipping two coins, or rolling two dice, are independent. Drawing two cards, however, are dependent, because the removal of the first card affects the possible outcomes (probability) of the second card.
The probability that the second coin matches the first is 0.5 .The probability that the third coin matches the first is 0.5 .The probability that the second and third coins both match the first is (0.5 x 0.5) = 0.25 = 25%
The probability is always 50/50 even if you flipped 100 or 1000000 coins.
The probability of tossing two coins that are different is 1 in 2, or 0.5.The probability of tossing something on the first coin is 1. The probability of not matching that on the second coin is 0.5. Multiply 1 and 0.5 together, and you get 0.5.
The conditional probability is 1/4.
The probability of the first coin landing heads is half (or 1/2). Similarly, the probability of the second and third coins landing heads are also 1/2 in each case. Therefore, the probability of having three heads is: (1/2)(1/2)(1/2) = (1/8)
First work out the probability of the first two coins being heads and then the last being tails. This is 1/2 x 1/2 x 1/2 which is 1/8 The next step is to find out how many different orders the coins can come in. In this case there are 3 possible orders (HHT, HTH, and THH). Multiply this by the above probability and you get 3/8. Therefore the probability of getting two heads and one tail is 3/8
The answer to the first question is 0.5. The answer to the second is not possible to work out.
The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.
Assuming I've understood your question properly...First, the number of coins doesn't matter in the slightest; only the first and last count, so the ones in between are irrelevant.Second, the first coin sort of doesn't matter. The only thing that matters is whether or not the last one matches it. Whatever the first coin is, the last coin could come up matching it or, with equal probability, come up not matching it.So the probability is 0.5.If you really want to convince yourself of this, list all the ways the coins could land (HHHH, HHHT, and so on to TTTT). There will be 16 of them. For 8 of those sixteen, the first and last coins will match.
The answer depends on whether or not the first coin is replaced before choosing the second. Unfortunately, that critical information is not provided.
196/5513, or about .0356=3.56%AssumptionI assume that you are asking what is the probability that the first three coins picked out of the pot are nickels. Obviously the answer would be different if, for example, you are asking what is the probability that if you pick all of the coins out of the pot what is the probability that at some point in picking out coins you will pick three nickels in a row.ExplanationP(three nickels in a row)=P(first coin picked is a nickel)*P(second coin picked is a nickel given that first coin picked is a nickel)*P(third coin picked is a nickel given that first two coins picked are nickels)=(50/150)*(49/149)*(48/148)=196/5513, or about .0356=3.56%
You have to buy it with your star coins in the first castle on world one