The Nyquist Limit can be disregarded as this is not a noiseless channel (faster signal = more noise, this channel's s/n ratio is provided as 20dB)
thus we use Shannon's result which says the maximum data rate of a noisy channel is X = H Log2 (1 + S/N) bps using 10Log10 S/N as our standard quality
2 = Log10 S/N --> S/N = 102 --> S/N = 100
X = 3000 Log2 (1 + 100) bps which gives you x = 19,974.63bps as your final answer.
~ Mike
------------------------------------------------------------------------------------
------------------------------------------------------------------------------------
------------------------------------------------------------------------------------
ALTERNATIVE APPROACHThe formula -
Shannon Capacity = Bandwidth * log2 ( 1 + Signal Power / Noise Power )
gets approximated to -
Shannon Capacity = Bandwidth * ( Signal to Noise ratio in dB ) / 3
assuming the fact that ....
Signal to Noise ratio in dB = 10 log10 ( Signal Power /Noise Power )
and also assuming
1 is much much less than Signal Power/Noise Power
So in the present case the approximate answer works out to
Shannon Capacity = Bandwidth * ( Signal to Noise ratio in dB ) / 3 ...
= 3KHz * 20 dB / 3
= 3 * 103 * 20 / 3 bits per second
= 20000 bits per second
~
ANIRUDDHA GHOSH
JADAVPUR UNIVERSITY
BSc Mathematics - 2004 - 2010
MCA - 2007 - 2010
~
C=log 2(1+S/N)=3000*log2(1+100)=19.975 bps
BLOB = (Binary Large OBject) An Oracle BLOB data type that contains binary data with a maximum size of 4 gigabytes. This maps to an Array of type Byte. See also: CLOB, NCLOB An Oracle CLOB data type that contains character data, based on the default character set on the server, with a maximum size of 4 gigabytes. This maps to String. An Oracle NCLOB data type that contains character data, based on the national character set on the server with a maximum size of 4 gigabytes. This maps to String.
A binary tree is type of tree with finite number of elements and is divided into three main parts. the first part is called root of the tree and itself binary tree which exists towards left and right of the tree. There are a no. of binary trees and these are as follows : 1) rooted binary tree 2) full binary tree 3) perfect binary tree 4) complete binary tree 5) balanced binary tree 6) rooted complete binary tree
What are the applications of Binary Tree.
What is called the Binary number system. on and off is a binary state.
Digital Data is data that is stored in binary, and a Digital Device is any device that works with binary data
255
Incomplete Binary Tree is a type of binary tree where we do not apply the following formula: 1. The Maximum number of nodes in a level is 2
Nyquist theorem for noiseless channel C= 2Blog22n. C= channel capacity in bps B= bandwidth in KHz 1 KHz= 1000 Hz C= 2*3*1000*log22. =6000 * log2 2. =6000 =6000 bps ..................................... Anu Chawla
+511
If we have a binary symmetric channel with an error probability Pe , then for error freecommunication over this channel, message from a source with entropy H(m) must be encoded by binary codes with a word length of at least H(m)/Cs whereCs = 1-[ Pe log(1/ Pe)+(1- Pe) log( ) ]The parameter Cs is called the channel capacity.Source: ewhatnhow.com/what-is-channel-capacity/
Plus or minus 65,535
36 hexadecimal and 24 binary sets.
because for the set binary number it will be 11111111 which is in hexadecimal is FF = 255
use to control signals in many circuits. it finds the maximum between two binary digits
If the number of levels is L, the maximum number of nodes N in a binary tree is N = 2L-1. For L = 5, N equates to 31 thus.
Output is be maximum when input binary number is 111111111111 and that value comes around 6.35mv.
A 5-bit binary counter, interpreted as an unsigned integer, has a range of 0 to 31. Interpreted as a two's complement signed integer, it has a range of -16 to +15.