Average acceleration over a certain time period is the difference in velocity, divided by the time. In this case, (4-2)/W.
It is 2/W ms-2.
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
A period of constant positive acceleration;a second period of zero acceleration; a third period of constant negative acceleration.
The wavelength will increase if the period increases.Proof:First define the terms: Wavelength = Lamda (λ), Velocity of propagation = v, frequency = f, period of oscillation = T. Frequency asks "how many waves per unit time (seconds usually)".Period asks "How much time (seconds) does it take for one wave cycle to complete".Also, frequency is inversely proportional to period, so f = 1/T. Also, T = 1/f.(Incidentally, note that as period (T) increases, then frequency (f) gets decreases. Or if frequency increases, then period decreases.)λ = v/forλ = vT. (by replacing f with 1/T)If the frequency decreases, OR/AND the velocity increases, then wavelength corespondingly increases.If the period increases OR/AND the velocity increases, then the wavelength increases.
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
It is 0.1 metre per second-squared.
Assuming that acceleration is constant during that time, just divide the change in speed by the time.
The idea is that you should: a) Calculate the change in velocity. b) Divide this change by the time. This gives you the average acceleration over the 20 seconds, in this case.
To find the average acceleration over the first 5.1 seconds of motion, divide the change in velocity over that time period by the time taken. Calculate the final velocity minus the initial velocity over 5.1 seconds to find the average acceleration.
Acceleration is the rate of change of velocity over time. So, if velocity is increasing over a period of time, there is acceleration present.
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.
ACCELERATION- A measure of the rate at which a defined amount of matter increases/decreases its velocity, measured in change in velocity over a period of time.=========================Answer #2:Acceleration is any change in the speed or direction of motion.
Dividing change of velocity by the time it takes to change the velocity. If acceleration is not constant, this will give you the average acceleration during the period; to get the instantaneous acceleration, you have to take the derivative of the velocity.
Acceleration is the rate of change of velocity over a period of time. When an object's velocity increases over a period of time, it is experiencing positive acceleration.