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10T because F=mV^2/radius in a circle. So if the velocity and radius are the same then you will just multiply the mass by ten (10mV^2/radius) giving you 10 times your period

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13y ago
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6d ago

The period of the second particle with the same electric charge but ten times as massive will be the same as the first particle in the same field as the period of a particle in a uniform electric field is not dependent on its mass.

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Q: If a second particle with the same electric charge but ten times as massive enters the field with the same velocity what is it's period?
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