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They would be roughly 14.49 cm apart, given a major axis of 35.6 AU, and perihelion of about .58720 AU. I am assuming that distances from the foci at perihelion and aphelion will be equal or very close to equal. The major axis minus twice the distance at perihelion gives a distance of about 34.426 AU between foci. 35.6 AU is to 15 cm as 34.4 AU is to x cm. This gives about 14.49 cm as the proportional distance between foci with the major axis scaled down to 15 cm.

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11y ago
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1mo ago

The distance between the foci of an ellipse is related to its major axis by the formula:

Distance between foci = 2 times the square root of (major axis squared minus minor axis squared).

If the major axis of comet Halley were scaled down to 15 cm, you would need to know the minor axis length to calculate the distance between the foci.

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Q: If comet Halley's major axis was scaled down to 15 cm how far apart would the foci be?
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