It is not possible because the average velocity is equal to the displacement in a given time interval, ie: V = (displacement) / (time interval) As the zero displacement average speed will also be zero.

Average velocity is change in position (displacement) divided by the interval.

The required velocity is the given displacement/the given time intervalin the direction from the starting point to the end point.

Yes, an object having zero average velocity over a given time may still be accelerating during that interval, relative to another object which is accelerating away from it (i.e., an observer on that other object would see the "zero average velocity" object moving away from him/her).

No. You need TWO positions at TWO times. The average SPEED is (distance between two positions) divided by (time interval).

With that information, you can find the average magnitudeof the accelerationduring that period of time. You can't tell what either the magnitude or directionwere at any time during, only the average magnitude for the whole interval.

That is called speed, or - if the direction is also relevant - velocity.

For the purposes of this explanation, velocity will be given in m/s. If it's starting position is the same as its stopping position, the radio controlled car will have an average velocity of zero meters per second. This is because average velocity is displacement/time interval. Displacement is change in position and is a vector quantity, which has magnitude and direction. Average velocity is the displacement/time interval, and is also a vector quantity, including the magnitude of the speed and its direction. If you start and stop walking at the same position, your displacement is 0m, even if you walked a distance of 100 miles, and your average velocity would be 0m/s. Refer to the related link below for an illustration.

Time, velocity and mass do not provide enough information. If you are given a time interval, t, then you need the velocity at the start of the interval (= u) and at its end (v). Then F = m*(v - u)/t

Average velocity is simply displacement over time. Instantaneous velocity is the velocity at any given instant, or the displacement over an infinitely small amount of time.

Their average velocity increases.

You need velocity at two points in time, and the acceleration must be constant. If the initial velocity is u ms-1 and the final velocity is v ms-1, and the time interval is t then t = (v - u)/a s.

Acceleration is the derivative of the velocity expression. If you have an equation for velocity, simply take the derivative of it and you will have an equation for the average acceleration.

(change in distance) divided by (time interval) = the object's average speed during that time interval.

The shift of velocity per unit of given time is called acceleration. The types of acceleration are negative acceleration and positive acceleration.

No. It is the change in velocity (not speed) during a given interval of time. It can be an increase or a decrease although a decrease is also called a deceleration.The distinction between velocity and speed can best be illustrated by an object going round in a circle at a constant speed. It is changing direction all the time so that its velocity is constantly changing. It is constantly accelerating even though it is travelling at constant speed.

Time = distance / average speed Average speed = 1/2 (initial + final)

If you know average speed then you cannot determine the acceleration: the very nature of being a average hides all the increases and decreases in speed which are the accelerations (technically, acceleration is change of speed in a direction). All average speed tells you is the constant speed at which you require to travel to cover the given distance in the given time; as the speed is constant, the acceleration is zero.

Distance = time * average speed (velocity) Average speed = Distance/time

Velocity is speed in a given direction.

Acceleration. Deceleration is a decrease of speed during a given interval of time.

Speed in a given direction is velocity.

Yes. it is possible to have average speed (even average velocity as vector, <v> ) to be zero. But the velocity in a given time is not zero. A famous example is electron in magnetic field. It has velocity but orbiting (classically), however it's average position is the same (quantum mechanically), so the electron stays there and do not go anywhere (no current).

There is average velocity, and there is instantaneous velocity. I don't think "overall velocity" is a concept generally used in physics; please clarify what you mean.

it can be calculated at a particular instant as it is total displacement in given time

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