Physics

Kinematics

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It is not possible because the average velocity is equal to the displacement in a given time interval, ie: V = (displacement) / (time interval) As the zero displacement average speed will also be zero.

No, you cannot have a zero displacement and a nonzero average velocity. If the object has not moved any where how can you attain a nonzero velocity? You cannot.

When the velocity is zero at the crossing of the time axis, the displacement must be a full maximum or minimum. Scroll down to related links and look at "Displacement - Velocity- Acceleration".

If the car has an average speed of 65 mph, when it returns to its starting point, it will have a displacement of zero and an average velocity of zero, because velocity has both speed and direction.

If the average velocity of a duck is zero in a given time interval, it can be said that the displacement of the duck is also zero. The duck did not leave its original position.

the displacement is zero.Note that distance travelled would not be zero though. as velocity doesn't signify anything abt distance travelled.speed will give you what distance you travelled.Since average velocity is zero, some component is negetive some positive or no movement at all. whichever case may be, the displacement will be zero.

If the displacement is not changing, the velocity is zero.

The average velocity is pretty close to zero. Velocity is a vector, so its average value is the total displacement divided by the total time. Since the racquet probably starts and finishes in the player's bag in the player's home, the average velocity is zero.

Speed is distance by time and velocity is displacement by time. If an object is moving with speed distance can never be zero but displacement can. So we say velocity can be zero.

For the purposes of this explanation, velocity will be given in m/s. If it's starting position is the same as its stopping position, the radio controlled car will have an average velocity of zero meters per second. This is because average velocity is displacement/time interval. Displacement is change in position and is a vector quantity, which has magnitude and direction. Average velocity is the displacement/time interval, and is also a vector quantity, including the magnitude of the speed and its direction. If you start and stop walking at the same position, your displacement is 0m, even if you walked a distance of 100 miles, and your average velocity would be 0m/s. Refer to the related link below for an illustration.

Yes, if, for example, a car races around a circuit, its total displacement is zero and so its velocity, at the end of every lap, is zero.

Zero average velocity does not equal zero dislacement. Zero average velocity equals zero average displacement. :) Wouldn't it be the other way around? Let's say I take my mouse from its center position (from which we'll define the displacement) and move it quickly to the right some arbitrary distance and then equally quickly back to the center. Then, I move it slowly the same distance to the left and equally slowly back to center again. Over this entire time, since the motions are symmetric (that is, the mouse spends the same amount of time moving in the positive direction as the negative), the average velocity must be zero. Also, we're back to the central position, so the net displacement must be zero. However, since we spent more time moving the mouse on the left, the time-averaged displacement must point to the left. Would you agree? Answer given by Neetu Singh Lambha.

Every time the unicycle returns to its starting point, the average velocity equals zero. The total displacement divided by the time.

As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.

Every time the unicycle returns to its starting point, the average velocity equals zero. C. The total displacement divided by the time.

Zero. That's the instant at which its velocity changes direction. In order to do that, its magnitude has to be zero at that point in time.

Yes, if it returns to its starting place, the average velocity for the cycle will be zero. The average SPEED, however, will not be zero.

The velocity is zero because the total displacement vector is zero.

If the average velocity of an object is zero is the average speed zero? no Velocity is a vector. Drive 50 mph east for 2 hours and then turn around and drive 50 mph west for 2 hours. 50 mph east is + 50, and 50 mph west is -50. Average velocity = (+50 + - 50) ÷ 2 = 0 Speed is not a vector, it has no + or - sign. 50mph east is the same as 50 mph west. Average speed = 50 mph Displacement = distance from beginning point to final point Average velocity = displacement ÷ time = 0 miles ÷ 4 hr = 0mph Distance = length of path traveled ÷ time Average Speed = distance ÷ time = 200mi ÷ 4 hrs = 50mph

An object moving in a circular path at constant speed will have a non-zero average speed and zero average velocity since velocity is a vector parameter,

When acceleration is zero.

Yes, dD/dt = d0/dt = 0 thusDisplacement D=0 and Velocity dD/dt=d0/dt = o.

The average acceleration from zero is the final velocity divided by the amount of time to reach that velocity.

After any whole number of revolutions, the total displacement is zeroand so the average velocity is zero.At any instant, the magnitude (speed component) of instantaneous velocity is(pi) x (distance from center of rotation) x (RPM / 30) units per second.

Because squaring a velocity removes its sign. A velocity may be negative, but it's square is always positive. If two velocities are +5 and -5, their average is zero. But both squares are +25, so the average square is +25.

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