Not enough information to answer--what's the method of propulsion? Gravity, pushing it, tying it to your cat, or attaching a model rocket motor?
To calculate the final speed, we need more information such as the force applied to the cart or the distance over which the force is applied. Without this information, we cannot determine the final speed of the cart.
F = ma a = F/m = 8/2 = 4ms-2.
96 newtons will do it.
m = 4.5kg v = 2.2m/s M = 15kg V = ? ---- velocity of ham and cart before: momentum of ham = pv momentum of cart = 0 after: momentum of ham and cart = (m+M)V momentum of ham + momentum of cart = momentum of ham and cart mv + 0 = (m+M)V mv / (m+M) = V (4.5*2.2) / (4.5 + 15) = 0.51 kgm/s
The speed of cart becomes fast when the horse applies more force
If the cart is moving at a constant speed in a straight line, it is in uniform motion. If the cart is changing its speed or direction, it is accelerating.
The final velocity of the cart can be calculated using the formula: final velocity = initial velocity + (net force/mass) * time. Assuming the initial velocity is 0 m/s, the final velocity would be: 0 + (500N / 38kg) * 4s = 52.63 m/s.
You push a 12.3 kg shopping cart with a force of 10.1 N. a) What is the acceleration of the cart.
The speed of cart becomes fast when the horse applies more force
A very basic model where we can assume there is no momentum loss during the collision... we need to calculate momentum, p.p = mvwhere m = 1 kg (the mass of the cart) and v = 0.5 m/s (velocity of the cart)p = 1 kg . 0.5 m/s = 0.5 kg.m/sAfter the collision the momentum will be the same, but the mass has doubled...so p = mv = 0.5 kg.m/s = (1 kg + 1 kg).vv = 0.5 kg.m/s / 2 kg = 0.25 m/s
V = 10cm/2s = 5cm/s Therefore, the cart's speed is 5cm/s.
.281 meters
The cart and the ball are both subject to the same gravitational acceleration, so they fall at the same rate. The cart's horizontal motion keeps pace with the vertical motion of the ball, allowing it to catch up. This is the principle of inertia and the relationship between vertical and horizontal motion.
You can increase the speed of an Yamaha 48 volt golf cart by installing a larger motor or more powerful batteries. This will produce more power to the wheels and more speed.
Max Speed 37-39 mph... that's pretty fast for a go-cart.
You push a 12.3 kg shopping cart with a force of 10.1 N. a) What is the acceleration of the cart.
Cart experiences a change in velocity(which is a vector quantity, not like speed). Cart's velocity on circular track has to be tangent to track at each point and because of that it has to change its direction. Speed may or not remain the same, you can't tell it changes in each possible case. Mass and weight remain the same.
There probably isn't a speed control on the golf cart itself, but on its engine. To get more or less speed out of it, you would need to mess with the governor (on the engine itself).
It should be completely safe for your son to ride a Razor Crazy Cart as long as he is under the correct supervision. The maximum speed is 12 miles per hour.
m = 4.5kg v = 2.2m/s M = 15kg V = ? ---- velocity of ham and cart before: momentum of ham = pv momentum of cart = 0 after: momentum of ham and cart = (m+M)V momentum of ham + momentum of cart = momentum of ham and cart mv + 0 = (m+M)V mv / (m+M) = V (4.5*2.2) / (4.5 + 15) = 0.51 kgm/s