Independent events with a probability of zero
Hi
Add the probabilities of the two events. If they're not mutually exclusive, then you need to subtract the probability that they both occur together.
What is the difference between dependant and independent events in terms of probability
Since there are 6 sides on every die that are equally likely to be rolled, the probability of rolling any given side once is exactly 1/6. The 2 events or the first and second dice roll are independent (the outcome of one does not influence the other) so to find the probability of both occurring you just multiply the probability of each event. Since each event has a 1/6 probability of occurring as stated before, The entire event has a probability of 1/6*1/6 or 1/36, which is approximately 2.78%.
If two events A and B are mutually exclusive, the special rule of addition states that the probability of one or the other event's occurring equals the sum of their probabilities. This rule is expressed in the following formula:Special Rule of Addition(5-2)Equation 5-2
In probability theory, disjoint events are two (or more) events where more than one cannot occur in the same trial. It is possible that none of them occur in a particular trial.
yss
No, the combined probability is the product of the probability of their separate occurrances.
The probability of two independent events occurring together is the product of both events. yw lazy odyssey users like me :)
Yes, it is possible for two dependent events to have the same probability of occurring. The probability of an event is dependent on the outcomes of other events, and it is influenced by the relationship between these events. So, it is conceivable for two dependent events to have equal probabilities.
Two independent events occurring.
These events are complementary. Let P(A) = probability event will occur. Then the probability it will not occur is: 1 - P(A).
It sounds like Bayesian statistics.
It is true.
If the probability of A is p1 and probability of B is p2 where A and B are independent events or outcomes, then the probability of both A and B occurring is p1 x p2. See related link for examples.
coincidence?
Multiply together the probability that each event would have of occurring by itself. For example, the probability of rolling a "3" on a single die is 1/6 ,because there are 6 different possibilities. And the probability of flipping a "heads" on a coin is 1/2 , because there are two possibilities. Then the probability of rolling a "3" AND flipping a "heads" is ; 1/6 x 1/2 = 1/12 .
The probability of at least one event occurring out of several events is equal to one minus the probability of none of the events occurring. This is a binomial probability problem. Go to any binomial probability table with p=0.2, n=3 and the probability of 0 is 0.512. Therefore, 1-0.512 is 0.488 which is the probability of at least 1 sale.