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.75

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12y ago
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6d ago

You can use Henry's Law to relate the solubility of the gas with the pressure above the water. When the solubility decreases to 1.0 g/L, the pressure above the water is proportional to this change, so it would also decrease proportionally to a value of 1.0/4.0 * 3.0 ATM = 0.75 ATM.

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Q: If the solubility of a gas in water in 4.0gL when the pressure of the gas above the water is 3.0 ATM what is the pressure of the gas above the water when solubility of the gas is 1.0?
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