Average acceleration during the time interval = (change on speed) / (time for the change) =
(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
-1.92 m/s2
2.75 m/s
Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
b. -1.92 m/s2Minutes per second is not a unit of velocity. If the question meant meters per second, the answer is correct.
2.75 m/s
-1.92 m/s2
2.75 m/s
B -1.92 m/s2
Using the definition of acceleration as change of speed / time, you basically need to know: * A time interval during which the object accelerates. * The velocity at the beginning of this time interval. * The velocity at the end of this time interval.
During constant acceleration, either the object's speed changes at a constant rate, or the direction of its motion changes at a constant rate, or both.
Acceleration = (speed at the end of some time interval minus speed at the beginning of the interval)/(length of the time interval)
Acceleration is equal to the change in velocity over the change in time [a=(vf-vi)/(tf-ti). a=(98m/s - 121 m/s)/(12s)=(-23m/s)/(12s)=-1.92m/s^2
Acceleration
Yes, acceleration is the how the velocity changes. This also includes when an object turns
We have this equation: Velocity after = Initial velocity + (acceleration * time) So, let's plug in the numbers into this equation. 98m/s = 121m/s + (acceleration * 12seconds) So, -23 = 12 seconds * acceleration dividing 12 from both sides, the acc. is -1.92m/s/s. (Yes, those are the UNITs of acceleration. And it's negative because the object slows down. )
Acceleration is a direction plus a speed. If either changes then the acceleration changes.