1/x+1/y
y/xy+x/xy
x+y/xy=12/24
12/24=1/2
1/2 is the answer.
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Reciprocals, or multiplicative inverses
It is 0.5
If two numbers are reciprocals, then their product is 1. If the product of two numbers is 1, then they are reciprocals.
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
If you multiply two reciprocals, their product must be 1.
I have a feeling that you wrote "opposite reciprocals"where you only needed to write "reciprocals".Their product is ' 1 '.
Two numbers are negative reciprocals if their product is -1. The numbers 1/2 and -2 are negative reciprocals. Their product is -1. This is often seen in problems involving the slopes of two lines. The slopes of perpendicular lines are negative reciprocals. Their product is -1.
sannie
(50 + 15) = 65 (50 x 15) = 750 1/50 + 1/15 = 13/150
The Two numbers are reciprocals of each number
They're known as reciprocals.
1