Take P to be the number of pigs and C to be the number of chickens. Because both anamals have a head, the sum of C and P is 143, or
C + P = 143
Because a chicken contributes 2 legs and a pig contributes 4, C times 2 plus P times 4 equals the total number of legs, or
2C + 4P = 478
divide this equation by 2 to get
C +2P = 239
Subtract the first equation from this one
P = 96
plug this into the first equation
C + 96 = 143
C = 47
96 Pigs and 47 chickens
Let c represent the number of chickens and p represent the number of pigs.Since chickens and pigs have one head each, 70 heads = c + p.Since chickens have 2 legs and pigs have 4 legs, 200 legs = 2c + 4p.Subtracting twice the first equation (140 = 2c + 2p) from the second, we get60 = 2porp = 30 pigsRewriting the first equation as c = 70 - p, we get c = 40 chickens.
chickens chickens
2c + 4p = 40 c + p = 13 so 2c + 2p = 26 so 2p =14 p = 7, c = 6 Check: 7 pigs = 28 legs, 6 chickens = 12 legs, total 40 legs. QED
C+P=26 2C+4P=70 Therefore C=26-P Therefore 2(26-P)+4P=70 Therefore 52-2P+4P=70 Therefore 52+2P=70 Therefore 2P=18 Therefore P=9 Therefore C+9=26 Therefore C=17 There are 17 chickens.
Heads: P + C = 24C = 24 - PLegs: 4P + 2C = 80Substitute, from heads: 4P + 2 (24 - P) = 804P + 48 - 2P = 802P = 32P = 16C = 24-P = 8====================Check:P + C = 16 + 8 = 244P + 2C = 4(16) + 2(8) = 64 + 16 = 80 yay!
35 pigs, 65 chickens
48 chickens 1 pig
Let c represent the number of chickens and p represent the number of pigs.Since chickens and pigs have one head each, 70 heads = c + p.Since chickens have 2 legs and pigs have 4 legs, 200 legs = 2c + 4p.Subtracting twice the first equation (140 = 2c + 2p) from the second, we get60 = 2porp = 30 pigsRewriting the first equation as c = 70 - p, we get c = 40 chickens.
On this farm there would be a total of 18 cows. There would also be 18 chickens, combining to make 36 heads and 104 legs.
14 chickens and 11 pigs.
two monkeys- 4 legs four pigs- 16 legs three chickens- 6 legs equals 26 legs
2 monkeys = 4 legs 4 pigs = 16 legs 3 chickens = 6 legs 26 legs total
14 pigs 8 chicken's Since there are 22 heads, let the number of pigs be x and the number of chickens be 22 - x. Since pigs have 4 legs and chickens have 2 legs, and there are 72 legs in all, we have 4x + 2(22 - x) = 72 4x + 44 - 2x = 72 2x + 44 = 72 2x + 44 - 44 = 72 - 44 2x = 28 2x/2 = 28/2 x = 14 (the number of pigs) 22 - x = 22 - 14 = 8 (the number of chickens)
Since PIgs don't fly yet, we will say they have no wings and we say chickens have 2 legs. Let C be the number of chickens and P be the number of pigs. Also, let's assume each chicken has two wings. 4P+2C=24 2C=12 so C=6 4P+12=24 4P=12 so P=3 6 chickens and 3 pigs. This answer must be changed when pigs fly!
This is not possible
2 monkeys = 4 legs3 chickens = 6 legs4 pigs = 16 legsTotal legs = 26
2 monkeys = 4 legs2 pigs = 8 legs3 chickens = 6 legsTotal = 18 legs