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If three number cubes are rolled all at once how many ways can you get 2 of the same number?
Wiki User
∙ 13y ago
I'm going to assume you mean standard dice, all three distinguishable, and exactly two of the same number.
First break the problem into smaller parts. First, determine the odds of getting the same number on the first two dice, and a different number on the third. Then just multiply this result by 3 and 216 to account for the first and last dice being the same, or the last two dice, then compute the total number of possibilities.
P(two dice being the same and last being different) = P(second die being the same as the first) * P(third die being different than the other two) = (1/6)(5/6) = 5/36
3*216*5/36 = 90 possibilities out of 216
Wiki User
∙ 13y ago
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