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If vx 3 meterssecond and vy 4 meterssecond what is the magnitude of the resultant velocity?
Wiki User
∙ 6y ago
You can calculate that with the Pythagorean theorem.
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is 5 ms-1.
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What is the formula for the magnitude of velocity?
The magnitude of velocity is calculated as the square root of the sum of the squares of the individual components of velocity in a specific direction. Mathematically, it can be expressed as |v| = sqrt(vx^2 + vy^2 + vz^2) where vx, vy, and vz are the x, y, and z components of velocity.
What is the formula for calculating magnitude of resultant vector?
The formula for calculating the magnitude of the resultant vector when adding two vectors is: magnitude = sqrt((vector1 magnitude)^2 + (vector2 magnitude)^2 + 2 * vector1 magnitude * vector2 magnitude * cos(theta)) where theta is the angle between the two vectors.
What would describe both speed and direction of a moving object?
Velocity describes both speed and direction of a moving object.
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
Which would provide the greatest gain in altitude in the shortest distance during climb after takeoff?
VX
What is the formula for calculating magnitude of resultant vector?
The formula for calculating the magnitude of the resultant vector when adding two vectors is: magnitude = sqrt((vector1 magnitude)^2 + (vector2 magnitude)^2 + 2 * vector1 magnitude * vector2 magnitude * cos(theta)) where theta is the angle between the two vectors.
What would describe both speed and direction of a moving object?
Velocity describes both speed and direction of a moving object.
What is the value of constant horizontal velocity?
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
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Can a component of a vector be greater than the vector itself?
No, the magnitude of a vector (in Euclidean space) is the square root of the sum of the squares of its components. This value can never be greater than the value of one of its own components.v = √((vx)2 + (vy)2 + (vz)2)v2 = (vx)2 + (vy)2 + (vz)2(vx)2 = -(vy)2 - (vz)2 + v2vx = √(-(vy)2 - (vz)2 + v2)Can vx > v?Substituting:√(-(vy)2 - (vz)2 + v2) > √((vx)2 + (vy)2 + (vz)2).Simplified:v2 > (vx)2 + 2(vy)2 + 2(vz)2.Substituting again:(vx)2 + (vy)2 + (vz)2 > (vx)2 + 2(vy)2 + 2(vz)2.Simplifying again:0 > (vy)2 + (vz)2.This results in a fallacy, since 0 can't be greater than a positive number. This wouldn't work even if both vy and vz were 0.
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If you throw an object with initial velocity Vo at angle theta what is the Vx and Vy components at the highest point ignoring any friction except the gravitational force?
At the highest point, Vx = VocosÏ´and Vy = 0.This is assuming that Ï´ is the angle made by Vo with the horizontal.(check the related links for more info on projectile motion)
